<p>i want to someone to explain me how to find HORIZONTAL ASYMPTOTES IN FUCTIONS?</p>
<p>i wanto to someone to explain me how to find horizontal asymptotes in function problems?</p>
<p>WRONG FORUM. </p>
<p>However, I got 800 on Math level 2 so i guess i might as well explain it to you:
To find the horizontal asymptotes, you have to compare degrees of the numerator vs. degrees of the denominator. If you have a higher degree in the numerator than that in the denominator, then then the horizontal asymptote does not exist. If you have a higher degree in the denominator, then the horizontal asymptote is y=0 or simply 0. If you have the same degree in the numerator and the denominator, then the horizontal asymptote is the divison of the coefficients. </p>
<p>For example: f(x)=1/x. The horizontal asymptote is 0.
f(x)=2x^2/x + 1, there is no horizontal asymptote.
F(x)= (2x^4 +1)/(x^4 -1), the horizontal asymptote is (2/1) or just 2.</p>
<p>U can write your question to [SAT</a> Subject Tests Preparation - College Confidential](<a href=“http://talk.collegeconfidential.com/sat-subject-tests-preparation/]SAT”>SAT Subject Test Preparation - College Confidential Forums) </p>
<p>i guess there will be people happy to help u!</p>