SAT Math Problem

[nothingto]

<p>^ </p>

<p>

QS/QV = 1/3</p>

<p>that means the length of QS is 1
and the entire length of QV is 3
(Obviously)
so using that we can determine that the length of SV by itself is 2</p>

<p>2nd part: PT /PR = 3/4</p>

<p>that means PT = 3 and PR = 4
(Again obviously)</p>

<p>so we need to find the value of the fraction area PST /area PQR</p>

<p>area of a triangle = bh 1/2</p>

<p>first lets find the area of PST.</p>

<p>the base is 3 as we determined line PT is 3. the height of SV is 2 as we determined above.
(3 x 2) x 1/2 = 3
thus the area of PST = 3</p>

<p>now let’s find the area of PQR.</p>

<p>base or length PR = 4 as stated in the original question
height or length QV = 3 as stated in the original question.
(4x3) x 1/2 = 6</p>

<p>so area PST / area PQR </p>

<p>= 3/6
= 1/2…or 0.5

</p>

<p>Compressed into:</p>

<p>1/2(2)(3)</p>

<hr>

<h1>1/2(3)(4)</h1>

<h1>3/6</h1>

<p>1/2</p>

<p>Lol!</p>