<p>One more approach for number 11: x = sqrt(3) or -sqrt(3), and y = 4 or -4. Let’s try the positive values first: </p>
<p>(x + 2y)^2 = (sqrt(3) + 2(4))^2 ~ 94.7</p>
<p>Now plug the answer choices into your calculator and you’ll see that (E) “matches up.”</p>
<p>Hey everybody,
I’ve been looking for the answer to this problem but I was not able to find it. Please excuse me if the question already exists but I really want to understand how to solve this problem.</p>
<p>Here it is. It comes from the official May 2002 college board test that is on the college board site.</p>
<p>If x - 3 <2 and y+1< -3, then the value of x+y could be
a) 0
b)1
c)2
d)4
e)8</p>
<p>x<5 (added 3 to both sides) and y < -4 (subtracted 1 from each side). Adding both equations results in x+y < 1. Therefore the answer is a), the only answer choice that is less than 1.</p>
<p>^I think that’s answer choice a)</p>
<p>This needs to be up-and-running again! I’m hungry for more of those level 4 and 5 questions… Here’s one from a previous SAT mock-test that I’ve done. I’d safely say it’s a level 5 geometry question and frankly a pain in the arse to answer.</p>
<p>Imagine you have a gorgeously simple right triangle with sides 3/4/5 (Yes, seemingly easy so far, right? …Hah.) Inside this triangle, there is an inscribed circle, tangent to those three sides, such as in the following picture:</p>
<p><a href=“http://d2slduh1u00bg.■■■■■■■■■■■■■■/T7909.png”>http://d2slduh1u00bg.■■■■■■■■■■■■■■/T7909.png</a></p>
<p>What is the length of the radius of this circle?
You see, this is why I just love/hate the SAT. It asks questions in such a blissfully simplistic manner, but when you sit down to think about it, you feel like jumping out a window.</p>
<p>Fwiw, your image is not for a 3-4-5 triangle. The answer to the problem is not really hard … as long as you know what to look for. The key is to evaluate the distances of the tangents. There is a simple formula that be memorized as well. </p>
<p>Sorry about the pic, I couldn’t find too many on Google Images which didn’t blatantly give the answer. I mean sure, when I saw how to solve the question, there was the “aaahhhhh” moment (And it made me love mathematics just that bit more) but I wouldn’t rank it as below level-4, that’s for sure.</p>
<p><a href=“http://www.math.wichita.edu/~richardson/inradius(big).gif”>http://www.math.wichita.edu/~richardson/inradius(big).gif</a></p>
<p>@Jor26029 , check that picture out! Was that how you managed to solve the question or did you use another method?
I wonder if it can be done with an equilateral triangle too?</p>
<p>Hey could anybody help me with these two problems from the first section of the blue sat book w/ 10 tests?</p>
<h1>1: in the 30-day month of April, for every 3 days it rained, there were two days it did not rain. The number of days in april on which is rained was how much greater than the number of days on which it did not rain?</h1>
<h1>2: a four digit integer, WXYZ, in which W, X, Y, and Z each represent a different digit, is formed according to the following rules.</h1>
<ol>
<li>X= W+Y+Z</li>
<li>W=Y+1</li>
<li>Z=W-5</li>
</ol>
<p>Please help me figure these out:)</p>
<p>Thank you.</p>
<p>Answer to number is 6 and number two is 5940.</p>
<p>Would that just mean that z is 0 and w is 5 and y is 4?is that what you were saying?</p>
<p>Alright, thank you very much!</p>
<p>The digits are 0,1,2,3,4,5,6,7,8, and 9. </p>
<p>How many 4 digit numbers with 8 in the hundreds place are divisible by 5? I think the answer is 180 (my calculations)</p>
<p>For the 2014 blue book (at least I think its 2014), in the second section of the second test, I do not know how to solve problem ten. It is the one involving two triangles and the ratio between two of their sides. Thank you in advance :)</p>
<p>From a jar containing 50 pieces of candy, of which 25 are red and 25 are green, ari has taken 3 red and 4 green pieces. He takes an additional 13 pieces from the jar. What is the least number of these additional pieces that just be red in order for ari to have more red candies than green candies among all the pieces he has taken? (Answer is 8)</p>
<p>The cost of a telephone call using long distance carrier A is $1.00 for any time up to and including 20 minutes and $.07 per minute thereafter. The cost using long distance carrier b is $.06 per minute for any amount of time. For a call that lasts T minutes, the cost using carrier A is the same as the cost for carrier B. If T is a positive integer greater than 20, what is the value of t?
(Answer is 40)</p>
<p>Could you explain how to got the second answer? I 7-6 on first, but for some reason decided go down 5-8 instead of 8-5.</p>
<p>Thanks:)</p>
<p>Sorry to be a bother lol:)</p>
<p>A box contains wood Beads, red glass beads, and blue glass beads. The number of glass beads is 4 times the number of wood beads. If one brad is to be chosen at random from the box, the probability that a red glass bead will be chosen is 3x the probability that a blue glass bead will be chosen. If there are 12 red glass beads in the box, what is the total number of beads in the box? Answer is 20</p>
<p>Also, the blue book 2nd edition, 2nd test 8th section number 12</p>
<p>(1/3)<em>12 = 4. That’s the number of blue beads. 12 + 4 = 16. (1/4)</em>16 = 4. 4 + 16 = 20, which is the total number of beads.</p>
<p>Explanation: There is 1/3 the number of blue beads as red beads. There is 1/4 the number of wood beads compared to glass beads. Since you can do all of this with one variable, you just solve for the total number of glass beads (16) and then solve for the total number of beads (1/4 the number of glass beads + # of glass beads). Make sense?</p>
<p>Nevermid, I figured the 1st one out. It’s just the one in the blue book that’s got me</p>
.gif){kind=link}
.gif</a></p>){kind=link}