<p>Four distinct lines lie in a plane, and exactly two of them are parallel. Which of the following could be the number of points where at least two of the lines intersect?</p>
<li>Three</li>
<li>Four</li>
<li>Five</li>
</ol>
<p>A I only
B. III only
C. I and II only
D. I and III only
E. I, II, and III</p>
<p>Whats the answer? does anyone have the CB explanation for it? because i try to pick an answer and its not opening up to the explanation and answer page. I think its D</p>
<p>Keywords lines, not line segments; and exactly two parallel lines.</p>
<p>Two parallel lines, two lines that cross them. The two non-parallel lines cross both parallel lines, and will (at some point) cross each other. Therefore, there are 5 intersections; four points when the non-parallel lines cross both parallel lines, and one from crossing each other.</p>
<p>oo sorry so the answer is B then..</p>
<p>Yeah,i guess B is da answer.assure us da answer.
Where hav u g0t this que?</p>
<p>why not D?</p>
<p>three of the lines can intersect at one point...
"where at least two of the lines intersect" big hint that there can be concurrency (three lines intersect at one point)</p>
<p>hey blah,good point.........i also now think your way is correct</p>
<p>this is an sat q of the day..only problem is that when u click on an answer choice it just takes u to the collegeboard.com website..the answer and explanation doesnt show up</p>
<p>yea, I'm going with D as well.
four is not possible because in order for that to happen, the other two lines would also have to be parallel.</p>
<p>It's D. Four is not possible because then you would have to have two sets of parallel lines but there is only one set of parallel lines. Three and five are both possible.</p>
<p>hm,now it's solved......it's D</p>