<p>This is from the Blue Book, so I'm going to guess a lot of people know how to solve this:</p>
<p>There's a spinner with numbers 1 through 6, and it is spun twice. The first number it lands on is "a" and the second number it lands on is "b". What is the probability that the fraction (a/b) is greater than 1?</p>
<p>All I got so far is that the first spin has a 5/6 chance, because 1 can't be spun for "a"... help?</p>
<p>Thanks in Advance</p>
<p>How many options for spin 1? 6</p>
<p>How many options for spin 2? 6</p>
<p>Repeats? yes</p>
<p>So 36 options</p>
<p>Think: if a is 1, then no matter what b is, it will be <1 (1, 1/2, 1/3, etc.) so-> 0/6 so far
a is 2, then (2/1=2) and (2/2, 2/3, 2/4, 2/5) so -> 1/6
a is 3 then (3/1=3, 3/2=1.5) and (3/3, 3/4…) so 2/6->
3/6
4/6
5/6 (6/1, 6/2, 6/3, 6/4, 6/5) but not 6/6</p>
<p>so I got (0/6+1/6+2/6+3/6+4/6+5/6)=15/36</p>
<p>For me, the key is recognizing that 1/1 is NOT >1. You only really have to do a=1 and a=2 before you figure out the pattern. Fast enough and correct, I trust?</p>
<p>Yup you got it 
Thanks so much, I was baffled by this question… I had a hard time just leaving it there unsolved.</p>
<p>I have another question: </p>
<p>There are 5 cards (since I can’t draw anything on here let’s just say “a, b, c, d, e”). If C cannot be placed on either end, how many arrangements are possible?</p>
<p>Packer, where do you get 0/6 ?</p>
<p>It is numbered 1 through 6 inclusively.</p>
<p>Nevermind I figured out… man how am I supposed to know to do this under pressure T_T</p>
<p>Edit* For anyone curious: the total possible combinations are 5x4x3x2=120. If c was placed on the right end, there are 4x3x2=24 combinations that are NOT possible. If c was on the left end, another 24 impossible combinations. 120-48=72 combinations. </p>
<p>Packer got 0/6 because if a is 1, there is no b that can satisfy the equation, so 0 possibilities.</p>
<p>0/6 is 0. Question asks you for the probability greater than 1.</p>
<p>0/6 is not a fraction.
0/6 is the probability that would allow if letter a is greater than 1.
There are 0 possibilities thus the probability is 0 if a is equal to 1.</p>