<p>72-11. In a club of 40 boys and girls, 3/4 of the members are older than seventeen and 22 of the members are girls. If 6 of the girls are seventeen years old or younger, how many of the boys are older than seventeen?</p>
<p>I got (c) 14. (3/4)40=30. So 30 members are older than 17. 22-6=16, so 16 girls are older than 16. 30=16 + x... x= 14. I'm pretty sure that's the correct answer.</p>
<p>The key here is thinking simply. I just did the problem like a little tree that branched out with the more information you know:</p>
<p>"In a club of 40 boys and girls, 3/4 of the members are older than seventeen and 22 of the members are girls. If 6 of the girls are seventeen years old or younger, how many of the boys are older than seventeen?"</p>
<p>You start off with 40 people altogether:</p>
<pre><code> 40
</code></pre>
<p>Then it says that three fourths of the members are older than seventeen. 3/4 of 40 is 30 so...</p>
<pre><code> 40
30 (>17) 10 (</=17)
</code></pre>
<p>It says that 6 of the girls are 17 or younger. Since there are ten people younger than 17, there must be 6 girls and 4 boys in that group. </p>
<p>Before that, it said that there were 22 girls altogether. Since there are six in the 17 and under group, there must be 16 in the older than 17 group...The rest of the people in that group must be boys, so: 30-16= 40</p>