<p>Can you please give me a detailed reasoning for this question. Am I over analyzing this, apparently hard for me, question. </p>
<p>When the positive integer "k" is divided by 7, the remainder is 6. What is the remainder when "k" + 2 is divided by 7?</p>
<p>A) 0</p>
<p>B) 1 This one is the correct answer.</p>
<p>C) 2 I always end up with this one.</p>
<p>D) 3</p>
<p>E) 4</p>
<p>How do you solve this??? This is probably simple algebra and I'm just missing something stupidly easy. Please help.</p>
<p>Since there’s 6 left over when you divide k by 7, adding 1 to k (k+1) will put that 1 into the 6 remainder to make another 7. The remainder will be zero.</p>
<p>Adding one to k+1 will increase the remainder from 0 to 1. Since k + 1 is evenly divisible by 7, k + 2 will have a remainder of 1, as after you take all the sevens in k + 1, you’re left with k + 2 - (k + 1), which is 1.</p>
<p>Hopefully that makes sense :)</p>
<p>just try a simple example and it’ll usually pertain for all possible values of k. Since K/7 has a remainder of 6, k can be 13. K+2 is then 15. Divide that by 7 and u get 1</p>
<p>What jman said. </p>
<p>In most cases, when you’re given a math problem with variables, you’ll want to use the method called “plugging in.” That is, you’ll plug in a number for the variable “k.”</p>
<p>So, we have to find a number K, that when divided by 7, has a remainder of 6. Three of these numbers are 13, 20, 27. Pick any of those. Then, you plug in the number for “K”
in the expression (k+2)/7. (13+2)/7; remainder 1. (20+2)/7, remainder 1. 29/7 remainder 1.</p>
<p>So, the answer is (B), 1.</p>
<p>Solving this using algebra is unnecessary and will take up too much time.</p>
<p>(Remember, plug in your number for ALL of the answers. There’s a very slim chance that your number MIGHT work for two answers. In that case, use a different number that still satisfies the given information until only one answer choice works).</p>
<p>@BlackPaint:</p>
<p>If the remainder is 6 for k, the remainder is 1 for k + 2. There are no exceptions. This question simply tests the definition of a remainder.</p>