<p>(x+y)^2 = 16 and (x-y)^2 = 9
what is the value of xy?</p>
<p>So I expanded and thought the answer was 7/2 but its 7/4...can someone explain as simply as possible?</p>
<p>(x+y)^2 = 16 and (x-y)^2 = 9
what is the value of xy?</p>
<p>So I expanded and thought the answer was 7/2 but its 7/4...can someone explain as simply as possible?</p>
<p>Also how can II (my sat math tutor said it was all 3) be right?
For throw 4, 2 made it and 2 didn’t so has is 2 greater than 2?</p>
<p><a href=“http://i44.■■■■■■■.com/254vubp.png[/url]”>http://i44.■■■■■■■.com/254vubp.png</a></p>
<p>(x+y)^2 - (x-y)^2 = 4.x.y</p>
<p>16-9=4xy</p>
<p>xy = 7/4</p>
<p>x^2 + 2xy + y^2 = 16
x^2 - 2xy + y^2 = 9</p>
<p>Subtracting second eq. from first gives 4xy = 7, xy = 7/4</p>
<p>As for the bean bag problem, your tutor has it right. They said for “all of the throws attempted”, meaning you lump all of the data together. You don’t consider each sub-category separately. (If you did, then clearly you are right: there are 7 people who together had 7 misses and no hits at all!)</p>