<p>How to factor these equations?</p>
<p>1.) x^3 +8x^2 + 22x +20 = 0</p>
<p>2.) x^3 + 2x^2 + x - 1 = 0</p>
<p>thanks</p>
<p>OK so I saw that this was posted by the US GOVERNMENT and I was like :**** are they really coming down on test answer discussion??? Just so you know- I was worried.</p>
<p>1) For the first one, factor by grouping. If there are four terms like there are in this equation, it’s a huge clue that they want you to do this. So here’s how you do it:</p>
<p>So put the first two terms together in parentheses like this: (x^3 + 8x^2)
Do the same for the second: (22x+20)
Your whole equation should look like: (x^3 + 8x^2) + (22x+20)= 0
Take out a common factor in each one, etc, etc.
Do you remember this? If not, you need to review it.</p>
<p>But uh oh, after doing it, I realized it doesn’t work. But it’s a good mistake to make because sometimes, factoring by grouping doesn’t always work.</p>
<p>Do you remember synthetic division? And you try factors that way? I recommend you buy the book Algebra 2 by Holt, or consult your textbook because you really need to know that and it would take pages and diagrams that I can’t do on this forum to explain it.</p>
<p>I doubt a question like this would appear on the SAT. (someone correct me if I’m wrong)</p>
<p>This question can be tackled in an easier way on the SAT.There would be 5 options given…so,one of those values should satisfy the equation.Hence,that would be your answer.</p>
<p>Yes ,you can always plug-in a value for x othan than 0,-1 or 1 ,2 for example and see what works</p>
<p>112358 is correct; there is no way this question will appear on the actual SAT.
Whatever material you’re using right now, it’s leading you the wrong way, bud.</p>
<p>Yeah where did you get those problems from, was that actually in an SAT review book?</p>
<p>If it was you should probably burn the book and buy yourself a blue book.</p>