<p>I want to know the algebraic way of solving this problem. thanks guys</p>
<p>for the annual school fundraiser, santiago has p pledges each for c cents per lap that he jogs. If his school track has 4 laps per mile and santiago raises a total of d dollars, how many miles did he jog in terms of p,c, and d?</p>
<p>1) 25d/pc
2)4pc/d
3)100d/pc
4)4pcd
5)25pcd</p>
<p>answer is choice 1).</p>
<p>damm yo… help a brother out…</p>
<p>Oh, I get it.
It is supposed to end up 100d/4pc or 25d/pc</p>
<ol>
<li><p>4pc represents the number of cents he gets per mile</p></li>
<li><p>d represents the amount he got in DOLLARS so you have to do 100d to convert it to CENTS (you need to have the same units)</p></li>
<li><p>divide the total (100d) by the number of cents per mile (4pc) and you get 100d/4pc or 25d/pc</p></li>
</ol>
<p>Thanks for the question lol, because I am studying too for the SAT</p>
<p>for the annual school fundraiser, santiago has p pledges each for c cents per lap that he jogs. If his school track has 4 laps per mile and santiago raises a total of d dollars, how many miles did he jog in terms of p,c, and d?</p>
<p>He makes pc per lap, so he makes 4pc per miles.
4pc * k = 100d (where k is the number of miles he ran) </p>
<p>We want to know how many miles he ran (k), so solve for k.</p>
<p>25d/pc…(1)</p>
<p>Thanks guys! appreciate the help. really i do. I UNDERSTAND IT NOW. i always seem to have trouble in these questions… any advice? just be practical? lol</p>
<p>For these kinds of problems, watch out for the change in units! There’s almost always a units switch embedded in the problem — dollars to cents, minutes to hours, feet to inches…the factor of that unit change is often partially cancelled by other numbers in the problem so that when you look at the answer choices, it’s harder to see what has happened.</p>
<p>And of course, no one is MAKING you do these algebraically in the first place. These problems are practically designed to fit the method where you make up numbers for the variables.</p>