SAT math questions help

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1

<p>Hey guys I am doing grubber book I have stumbled upon these 2 questions that I can't solve.</p>

<p>First question I solved it but I need other way of solving the algebrical way,so I get more ideas onto how to solve in different way.</p>

<p>1)The Mavericks baseball team has a won-lost ratio of 7/5. if the team played a total of 48 games and no game ended in a tie, how many more games have the Mavericks won than they have lost?</p>

<p>I have solved this one like this 7/12 * 48 = 28won;so lost = 48 - 20 = 8;</p>

<p>I wanted to know if there is other way to solve this?</p>

<p>2)When the Apex store first opened,the ratio of cats to dogs was 4 to 5. Since then, the number of cats has doubled,while the number of dogs has increases by 12. If the ratio of dogs to cats is now 1 to 1, how many cats did the store have when it opened?</p>

<p>Thanks in advance.</p>

2

<p>For the first one, here is an algebraic solution:</p>

<p>7x+5x=48
12x=48
x=48/12 = 4
So 7x=28, and 5x=20. Finally, 28-20=8</p>

3

<p>For the second, there are initially 4x cats and 5x dogs.
Since the number of cats are doubled, there are now 2(4x)=8x cats.
Since the number of dogs increases by 12, there are now 5x+12 dogs.</p>

<p>The ratio of dogs to cats is 1 to 1. This means the number of dogs and cats is equal.
So 8x=5x+12
3x=12
x=4.</p>

<p>The number of cats when the store opened was 4x=4*4=16.</p>

4

<p>Your solution to the first one is actually fine. Here is a slighly different approach:</p>

<p>Start with 7 and 5. The sum is 12. You need a sum of 48 so multiply both by 4.
Now you have 28 and 20…so the difference is 8.</p>

<p>For the second one: you could do it algebraically –</p>

<p>Call the ration 4x:5x, then let 8x = 5x +12. You’ll solve for x and then plug back in to get the number of cats and dogs.</p>

<p>But if you are patient, you can also solve this by playing with numbers:</p>

<p>Start with 4 cats, 5 dogs. Double the cats, add 12 to the dogs…you get 8 and 13…nope</p>

<p>How about 8 cats, 10 dogs…you get 16 and 22, still no good.</p>

<p>How about 16 cats, 20 dogs? Double 16 and add 12 to 20 – you get 32 both times.</p>

<p>In general, playing with numbers often allows you to solve ratio problems without using algebra.</p>

<p>p.s I see Dr Steve and I are both up early today</p>

5

<p>This the first question answer , i think this way would be longer , but this is what works out for me </p>

<p>

<a href=“http://tapatalk.com/mu/025b82d1-be80-085c.jpg[/IMG]”>http://tapatalk.com/mu/025b82d1-be80-085c.jpg

</a></p>

<p>I hope it’s clear</p>

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<p>Thanks for pckeller and DrSteve you help me alot hopefully I am solving alot of questions and getting more and more ideas,because I aiming to get 800 in math.
I just need to solve more.</p>

7

<p>The second question , again long method but for me i prefer it .</p>

<p>

<a href=“http://tapatalk.com/mu/025b82d1-c11b-3684.jpg[/IMG]”>http://tapatalk.com/mu/025b82d1-c11b-3684.jpg

</a></p>

<p>Again , i hope it’s clear .</p>

<p>I LOVE ALGEBRA d:</p>

8

<p>Yeh @ freedomEagle nice way of solving :).</p>

<p>The logic I pointed is pretty simple for first question since there are 7 and 5,so there are 7 + 5 groups = 13,so its 13 object,so 7/15 * 48 would get how much won or you could do </p>

<p>48 / 13 * 7 that makes more sense,but less faster.</p>

9

<p>I guss I wasn’t much of a help then . Allright , gd luck anywayz .</p>

10

<p>Aight lets see…hmmmm. Well your first method is fine. Ima show you how to do the second one with a far easier method than the poster above who posted an incredibly long solution. Remember that these ratio problems have the same basic concept.</p>

<p>the ratio of cats to dogs is 4/5. so we will say</p>

<p>c/d = 4/5</p>

<p>now for the second part of the problem. The ratio becomes even when the number of cats doubles and 12 more dogs are added. So do the same thing again</p>

<p>2c/d +12 = 1</p>

<p>we need to isolate d in the second part to get the value of c to plug back in the 1st part so </p>

<p>2c = d + 12</p>

<p>d = 2c -12, plug this back in for d in c/d = 4/5</p>

<p>c/2c-12 = 4/5</p>

<p>5c = 8c-48</p>

<p>-3c = -48</p>

<p>c = 16</p>

11

<p>@eagles94</p>

<p>I see thanks for the explanation for this different way to solve it makes sense.
We also inputted d for 4/5 since we know they are both 1. Yes thats nice :).</p>

<p>Its good to know a problem more than one way incase in the sat you get a problem where one of the ways posted is possible.</p>