SAT Math Questions

Test Preparation SAT Preparation
1

<li><p>Two cyclists start biking from a trail’s start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
A. 2 hours
B. 4 ½ hours
C. 5 ¾ hours
D. 6 hours
E. 7 ½ hours</p></li>
<li><p>Jim can fill a pool carrying bucks of water in 30 minutes. Sue can do the same job in 45 minutes. Tony can do the same job in 1 ½ hours. How quickly can all three fill the pool together?
A. 12 minutes
B. 15 minutes
C. 21 minutes
D. 23 minutes
E. 28 minutes</p></li>
<li><p>If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks?
A. 2 minutes and 44 seconds
B. 2 minutes and 58 seconds
C. 3 minutes and 10 seconds
D. 3 minutes and 26 seconds
E. 4 minutes and 15 seconds</p></li>
</ol>

<p>here are some problems i don’t quite understand…could someone aid me into to understanding.</p>

<p>…more questions to come</p>

2

<p>For the first one, just make a table</p>

<p>3 hours - The guy who left three hours ago has already gone 18 miles and the other guy has 0</p>

<p>4 hours - First guy has 24 because he has traveled another hour and the other guy has 10</p>

<p>5 hours - First guy has 30 second guy has 20</p>

<p>6 hours - First guy 36 / second guy 30</p>

<p>7 hours - First guy 42 / second guy 40</p>

<p>.. So it has to be 7 and 1/2</p>

<p>(hope I didn't do it wrong, lol that'd be embarrassing :P)</p>

<p>I'll do the others in a minute</p>

3

<p>Q1. When C2 starts, C1 is 18 miles ahead of him. C2 is (10-6) = 4 mph faster than C1, so it will take him (18/4) = 4.5 hours to catch up to C1. (That's 4.5 hours from the time that C2 started, which is what the question asks for; it's also 7.5 hours from the time that C1 started).</p>

<p>Q2. If the pool has P gallons, then Jim fills at a rate of (P/30) gallons per minute, Sue at (P/45) gal/minute and Tony at (P/90) gal/minute. Working together, they will fill at a rate of
(P/30) + (P/45) + (P/90) gallons per minute
= (3P/90 + (2P/90) + (P/90)
= 6P/90 = P/15 gallons per minute</p>

<p>How long will it take them to fill up P gallons? Answer is (P / joint rate)
= P divided by (P/15)
= P * (15/P) = 15 minutes.</p>

<p>Q3. Same logic as Q2, work it out.</p>

4

<p>Q1. B</p>

<p>Q2. B</p>

<p>Q3. A</p>

5

<p>So typically all you need to do for Q2 and Q3 is get the overall time for each person by adding and then getting the average time of one from that combined number.</p>

<p>It sort of like an average...i thought it was the average of the values...i guess not..thnx</p>