<p>In square ABCD, vertex A is at -1,-1 and vertex C is at 4,2. What is the area of square ABCD?</p>
<p>I got 34. </p>
<p>The Answer is 17. </p>
<p>What the hell, somebody explain !</p>
<p>Area of square = 1/2 (diagonal)^2
diagonal = AC = (applying distance formula)...
AC = sqrt (5^2 + 3^2) = sqrt (34)</p>
<p>Now area = 1/2 (diagonal)^2
= 1/2 * 34
= 17</p>
<p>Oh damn, i labeled the square wrong =(. </p>
<p>Thanks alot bro</p>
<p>^^ do we have to know that formula?</p>
<p>No, just remember the diagonal is root2 times the side of the square and u can do it. Thats how u get the formula too.
Area=side^2=(diagonal/root2)^2 = 1/2 x diagonal^2</p>
<p>yeah i got the diagonal mixed up with the side.
haha, i think im going to go cut myself.</p>
<p>lol spidey,i was going to ans that....but your ans is more than good</p>