<p>yea i put that too</p>
<p>Topographical vs. Mineralogical. Definately the answer. No question about it.</p>
<p>I'm almost 99% positive that I could have done AT LEAST 200 points better than what I did today. I know, most people say that it's onl a feeling when you do bad, but I KNOW I did bad. I was so upset that I couldn't finish such an easy essay (it was the perfect topic for my subject. The Stranger, Fahrenheit 41, and WWII, my examples, fitted perfectly) because they gave us 5 minutes less than what they were supposed to (20 min as opposed o 25 minutes) and that she didn't warn us huw much time we had until we had 5 minutes left (this might be okay for multiple choice, but you HAVE to tell us the time BEFORE the 5 minute barrier) that I messed up on he following Math and RC section.</p>
<p>Definetlly cancelling this one.</p>
<p>what about the last question in the venice passage? I think it was about which thing the authors discussed in common.</p>
<p>mozillameister: can't you complain to collegeboard about not being given 25 min to do the essay? If it doesn't do any good for you this time, at least make sure the proctor doesn't screw up the next round of testing for people. </p>
<p>Also, I hope you're really sure that you did as bad as you think you did. I almost cancelled my April 2300 score b/c I thought I bombed it.</p>
<p>there was one question on the math and it was like, a 10 digit number is made up of ne combination of 4's and 5's, which is tru about the statement</p>
<p>i narrowed it down to it is always divisible by 4 and it is not a prime number. but if it is always divisible by 4, doesnt that make it not a prime numbeR? i was confuesd</p>
<p>it number cannot be a prime number.
how can the number always be divisble by 4?</p>
<p>for the x^2+y^2+z^2=9 I got two answers. one answer was x=0, y=0, and z=3? I'm certain that 0 is an integer. I can't recall if the prob. said all the numbers were greater than 0.
However, I decided to play it safe and stuck with the 2,2,1 answer.</p>
<p>i dk but i tried out a lot of the different oens on my calc and it always worked out that it was divisible by 4, i just put that its not prime cuz there mightve been one time where it was not divisble by 4 but ic ouldnt find it</p>
<p>4555555555/4= 1338888888 remainder 3</p>
<p>i didnt get that 1 about the 4 and 5's</p>
<p>basically, it'll never be prime because a number that ends in 4 will always be divisble by two, and a number that ends in 5 will always be divisble by 5</p>
<p>so the answer is its not a prime number?</p>
<p>yep, doesn't that make sense?</p>
<p>So can anyone explain the if a number is in x blah blah problem well?</p>
<p>The question is</p>
<p>If a number is in X, it is ALSO in y.</p>
<p>Which of the following statements are true if the above is true?</p>
<p>I basically narrowed it down to two choice</p>
<p>If a number is in Y, it is in X
If a number is not in Y, It is not in X</p>
<p>NishtDawg: I think you had a Q about the weatherman passage - I put tempered approval instead of unqualified appreciation b/c the two writers weren't totally pleased with their weatherman and even the second writer implied that he knew that his weatherman was faking some things. Both writers accepted their weatherman's performance w/o total appreciation.</p>
<p>backfire: if not in y, then not in x.</p>
<p>they had to be "positive" integers</p>
<p>if a number is not in Y, it is not in X</p>
<p>basically, the statement from the question makes it so that every number that is in X is also in Y. however, this doesn't mean that every number is Y is also in X</p>
<p>take these two lists</p>
<p>X- 1,2,3,4, 5, 6
Y-1,2,3,4,5,6,7,8,9</p>
<p>therefore, if a number is not in Y, it cannot be in X</p>
<p>pandora, the options were</p>
<p>tempered appreciation and unquailifed approval!!! LOL</p>
<p>and i put unqualified approval, b/c i figured that the author doesn't appreciate the glib behavior, but approves of it because the weatherman is a television personality</p>
<p>ah i see. Grrr two wrong... hopefully no more stupid mistakes. 780 is an ok score</p>