SAT Subject Test January 2009: Math Level 2

<p>wikipedia says that you can define a partial inverse in which you limit the domain of a the said function( tilted parabola) so that it is indeed a defined function.</p>

<p>Yeah, but if you limit the domain of the function, the inverse will have the same limit on its range. And, therefore, the two graphs won’t be identical. And thus, the two functions aren’t equal.</p>

<p>Either way, I agree, that question is messed up (unless we are missing something…).</p>

<p>I guess the next question is… does collegeboard accept complaints? lol</p>

<p>good point, i guess we’ll just have to wait and see what the answer and explanation is from collegeboard, unless someone can come up wi something b4 that time.</p>

<p>What would be the result if I omitted 10 and got about 3 wrong?
The worst version of Math 2 I’ve taken to date!</p>

<p>Haha how would we know the correct answer to the question? It’s not like CB releases answers to their subject tests.</p>

<p>Are you guys sure that something can be symmetric about a point? I’m not sure it can… Don’t you always need an axis of symmetry?</p>

<p>

</p>

<p>You gotta be kidding me dude. 1 omit and 2 wrong still gives you an 800. In fact you can probably afford to miss one or two more and still get an 800.</p>

<p>Haha you all seem so smart. I felt pretty smart on the last question when I got it right after MANY unsuccessful attempts heee =). Hoping for a 700+, but idkk… Barron’s prepared me well.</p>

<p>Oh and can anyone explain to me the standard dev one? I put something like 8,9,10,10,10,10,11,12… I just had no real idea…</p>

<p>Eryi was this test definitely harder than the other math II’s you’ve taken? What would you guess for a possible curve?</p>

<p>was the answer to the trapezoid one 7ish or 8ish?? there seems to be a discrepancy on this thread about that</p>

<p>Well, I’ve only taken the exam about 3 times (including todays) and it was the hardest IMO. I don’t really know how the curve stuff works, but I was hoping to break my 680. 10 points more please?</p>

<p>For the trapezoid problem… I got 7.-something.</p>

<p>1 omit, between 2-4 wrong. 800? Yes?</p>

<p>For the trapezoid, you first found the area of the square in the middle of the trapezoid. You then found the area of the triangles on the side. BUT, the triangles weren’t really triangles as they were a little curved. So then you found the area of the triangles and added them to the area of the square. Because the triangles were a bit curved, the answer was a little more than what you got. I don’t remember what was the answer, but say you got 4.25, then the actual answer couldn’t be anything less than that, but it also couldn’t be something like 8, so it was something like ~ 4.80</p>

<p>Those weren’t the actual numbers though.</p>

<p>When will scores be out?</p>

<p>

</p>

<p>For March 14, 2009 SAT:
Regular Registration Deadline (postmark/submit by) … February 10, 2009.</p>

<p>Clever!</p>

<p>^ Very! Insecurity on our part –> More profit for CB!!</p>

<p>isn’t it?
hate those mother****ers so much…
but at least in this particular situation, us subject takers don’t have to worry since there aren’t any subject tests offered in march anyway =P</p>

<p>

This is false. They asked for the area under the TRAPEZOID, not the curve. So the answer isn’t a little more than what you think it is. It IS what you think it is. The answer is 7.92, final.</p>

<p>

Yeah, things can definitely be symmetric around a point. In fact, the (loose) definition of an odd function is a function symmetric around a point (the origin). You’ll see this when you take precalc.</p>

<p>I’m sure the period of f(x)=|tan2x| is pi/4 cuz period of tanx is pi
period of tan2x is pi/2
absolute value makes all negative results positive
so the graph repeats twice faster</p>

<p>Samir, that argument would be valid for sine or cosine, but not for tangent. See, the two halves of tan(x)'s normal period don’t look the same when absolute value’d. Therefore, the absolute value has no effect on the period and the graph DOESN’T repeat faster. Honestly, just graph it if you need more proof.</p>

<p>thank you
i see my mistake=)
i just forgot that</p>