<p>how do i use calculator to solve polars like -2= Θ+sin(2 Θ)?</p>
<p>bump! i was just going to ask this…how do you graph the r??</p>
<p>To graph the r, go to mode and then change from (most likely) function to polar. You also have the option of parametric and a few others. It’s pretty self explanatory after that, just go to y= and tada!</p>
<p>OP: F2 solve would be my guess. But I’ve never seen a problem asking something like that, where you add the theta to the sin/cos/whatever. Most of the problems I’ve seen are in some form of r=A<em>cos(angle</em>B) where A and B are constants. Are you sure you posted the problem correctly?</p>
<p>Original problem was 2005 Q2 #b.
Given -2 = rcosΘ=(Θ+sin2Θ)^2*cos(Θ), it gives the answer Θ = 2.786</p>
<p>can you use the calculator to find the area of it?</p>
<p>Huh. Sorry, can’t help you I guess.</p>
<p>For the area, I’m not sure if it is possible to find the area of a graph. But, it’s really not too hard to do the integral on your calc.</p>
<p>that’s what i meant…i only know how to do it for normal curves…not the polar ones…</p>
<p>The polar integral is the integral from theta initial to theta final of the (radius function squared over 2)dr.</p>
<p>Given -2 = rcosΘ=(Θ+sin2Θ)^2*cos(Θ), it gives the answer Θ = 2.786 </p>
<p>Anyone knows how to get the answer?</p>
<p>my teacher did this one in class the other day</p>
<p>you have to graph the curve in FUNCTION mode, and then graph y=-2, and find where they intersect, and thats theta. cuz you cant do intersects with polar</p>
<p>:)</p>
<p>how do you graph the curve in FUNCTION mode</p>
<p>convert the polar to cartesian somehow? Or convert y=-2 to polar?</p>