<p>1.) If you rolled a die, the probability of getting a 1 would be 1/6. If you rolled a die 3 times, what would be the probability of getting a 1 all 3 times? (I can't figure out how to set this up.)</p>
<p>2.) In the standard (x,y) coordinate plane, what is the distance between the points (s, -1) and (-1, s)? (don't know how to set this one up either)</p>
<p>3.) Salma, Luis, and Veronica are siblings. Salma is half as old as Veronica, and Veronica is 3 years younger than Luis. If Luis is L years old, what is the sum of the three children's ages?</p>
<p>4.) For particular real numbers 'p' and 'q' the equation </p>
<p>(p(x+2)^3) + (q(x+2)^2) = 1 has one real solution, x = a</p>
<p>What is the solution of the equation</p>
<p>px^3 + qx^2 = 1</p>
<p>5.) Which of the following equations would intersect the graph of </p>
<p>(((x+3)^2)/16) + (((y-1)^2)/36) = 1</p>
<p>if the equations were graphed in the standard (x,y) coordinate plane?</p>
<p>c.) x = 1
d.) y = x
e.) y = x^2</p>
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<p>Please explain and if you know any shortcuts that are usable on the Ti-84, let me know.</p>
<p>1) (1/6)^3… since there are 3 different events, u must multiply them together. There is a 1/6 chance u get a 1, so multiply 1/6 and 1/6 and 1/6.
2) I assume u need to use the distance formula which is the square root of (x-x)^2 +(y-y)2… So it would be the square root of (s–1)2 + (-1-s)^2… then solve from there. Dont forget to foil and not simply square each term.
I cant solve the rest right now, but if I have time, ill try. Here is a quick tip: Pick random numbers and see if they work. Instead of algebraically solving for a problem, pick a random number for and see if the number works by looking at the multiple choice answers. Sorry, its kind of hard to explain</p>
<ol>
<li>Just multiply each roll together: (1/6)<em>(1/6)</em>(1/6) = 1/216</li>
<li>The distance formula is sqrt((x2-x1)^2+(y2-y1)^2). PLugging in the values we get sqrt(((-1)-(s))^2+((s)-(-1))^2) which equals sqrt(2(s+1)^2)= (s+1)sqrt2</li>
<li>Just set up a few sytems of equations. (I’m assuming they want the answer in terms of L). We have L=V+3 and V=2S. Therefore, V=L-3 and S=(L-3)/2. Adding all the ages together we get L+(L-3)+((L-3)/2) = (5L-9)/2</li>
</ol>
<p>Adding onto GreyWolf’s post on number 5, it may be difficult (I don’t know your math level…) to graph it on the calculator. You could, however, graph it roughly on paper and graph the answer choices on the calculator to see the answer.</p>
<p>Number 4 is really tricky. I’m not sure if what I will be explaining is accurate. It seems that the given graph is shifted to the left 2 units (x+2). So the answer might be a+2…</p>