<p>Help please?</p>
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<p>Bump. I’d like to know the solutions for these too.</p>
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<li><p>The way to maximize this area is to make it a right triangle with 7 and 10 as the legs. That means the base is 10 (or 7) and the height is 7 (or 10). 1/2 * 7 * 10=35. C.</p></li>
<li><p>I’m not sure of an algebraic way to do this one, but it’s fairly simple to do just by looking at it. Basically you can just draw all the possible ways onto the grid.</p></li>
<li><p>This one is easiest done by just marking all of the points on the grid and connecting them. You will see that it looks like a diamond, which when you turn it sideways is actually a square.</p></li>
<li><p>For any two integers you multiply, the units digit will be the product of the units digits of the two numbers you multiplied. For example: 5<em>7=35. 35</em>87=3045. as long as the final digits of each factor remain the same, the final digit of the product will remain the same.</p></li>
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<p>In this case, you want to find the two consecutive even or odd integers (because they’ll be separated by k) which multiply together to equal 9. You can do this either by trial and error or algebraically, but trial and error will be faster. Since the product you’re looking for is odd, you can rule out all pairs of even integers, because their product will be even.</p>
<p>Possible pairs then are: 1<em>3, 3</em>5, 5<em>7, 7</em>9, 9*11, etc.</p>
<p>The only one of these which yields a nine in the units digit is 9*11. So let’s assume that j, k, and n equal 9, 10, and 11 respectively. That means that the units digit of k is 0. A.</p>
<p>For the first one, doesn’t the third side have to be between 3 and 17. So, for example if it was 16, wouldn’t the area of the triangle be greatest then?</p>
<p>^It would be next to impossible to find the area of the scalene triangle you are talking about.
Remember,each SAT math problem should be done under 30 seconds.</p>
<p>17) You’ll have to draw the ways and see.No other/algebraic way around it. Im getting six.</p>
<p>No. That would perhaps yield the largest perimeter, but the largest area comes when you maximize the base and the height i.e. a right triangle.</p>
<p>pixie: that 30 second rule. does that actually work? i read about it in grammatix but it seems unbelievable lol</p>
<p>Well,it works for me.I would say 30 seconds is an average.It takes me 5 seconds to do a few of the problems,while a few others take around 50 seconds.</p>
<p>I’m still a little confused by that.</p>
<p>If the triangle weren’t a right angled triangle, the max the bottom length could be is 16 and the max the height of the triangle could be is 6.</p>
<p>i.e.:
<a href=“http://i83.■■■■■■■■■■■■■■■/albums/j283/ta_lia/triangle.jpg[/IMG]”>http://i83.■■■■■■■■■■■■■■■/albums/j283/ta_lia/triangle.jpg
![http://i83.■■■■■■■■■■■■■■■/albums/j283/ta_lia/triangle.jpg[/IMG]](http://i83.photobucket.com/albums/j283/ta_lia/triangle.jpg%5B/IMG%5D){kind=link}
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<p>Then it could be 16*6 / 2 = 48 which is bigger than 35?</p>
<p>Another thing about question 18 is</p>
<p>though i do understand and figured out hwat you said about drawing the diamond/square</p>
<p>i don’t undderstand why 18 D is wrong “lie on a pair of intersecting lines”</p>
<p>if you exactly m distance of 3 away you’ll aways be on a point of intersection so why is this wrong?</p>
<p>That won’t work for the triangle because while you can have a triangle with sides of those lengths, there is no way for the height to be 6 while the base is 16. Get a ruler and try to draw it and you’ll see what I mean.</p>
<p>For number 18, I understand what you mean. This is just a case of somewhat ambiguous wording. What it means by a pair of intersecting lines is that if you were to mark every point at a distance of 3 is that you could draw two intersecting lines that would pass through each of the points.</p>
<p>Thank you very much!</p>
<p>Could you also help me out with these 2 that I had trouble with?</p>
<p><a href=“http://i83.■■■■■■■■■■■■■■■/albums/j2...lia/help-2.jpg[/url]”>http://i83.■■■■■■■■■■■■■■■/albums/j2...lia/help-2.jpg</a></p>
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