<p>---> x^2 + y^2 -3y = 0</p>
<p>---> x^2 + y^2 -3y + 9/4 - 9/4 = 0</p>
<p>my algebra is a bit rusty. i understand where the + 9/4 comes from. but what about the
-9/4?</p>
<p>ANY HELP IS APPRECIATED!! THANK YOU!</p>
<p>ur actually kiddin us arent’t u?</p>
<p>how does that help me loop!</p>
<p>can someone pls help. :D</p>
<p>weezy post in the right forum please.</p>
<p>awww i thougth my buddies could help me out. =[</p>
<p>wow in a transfer forum</p>
<p>You didn’t even ask a question, you just wrote two equations. If the question is why are they equal, then (+9/4-9/4)=0, therefore x^2+y^2-3y=x^2+y^2-3y-9/4+9/4</p>
<p>Now that your “question” has been answered please use the right forum next time.</p>
<p>—> x^2 + y^2 -3y = 0</p>
<p>—> x^2 + y^2 -3y + 9/4 - 9/4 = 0</p>
<p>my question is how you derive the second equation fromt he first one. in particular where does the -9/4 come from. i apologize for posting in the wrong forum! will not do in the future.</p>
<p>Read my post directly above yours…</p>
<p>completing the square? wow this is alg2 stuff…</p>
<p>weezy baby is this a homework problem?</p>
<p>Weezy!! You’re “completing the square.” It’s a trick you use to make your life easier to solve an equation in algebra. SO, I believe the original problem is X^2+Y^2-3Y, correct? If that’s the case, this is what you’re doing: Ignore the X^2 and just focus on Y^2-3Y for now. You’re adding an “imaginary” number: 9/4, reason being is you’re squaring half of the previous term’s coefficient, (3/2)^2=9/4. NOW, since you have added a number that never existed in the original problem, you’ll need to subtract it.</p>
<p>So that whole problem comes out to be -> X^2+(Y-3/2)^2-9/4=0. NOW SOLVE IT YOURSELF.</p>
<p>lollllll cool</p>
<p>this is hilarious</p>
<p>LOL. how did a post about math get these many views… i think we all need to take a break from this site.</p>