<p>So, I just saw this strange geometry problem that I know shouldnt be that hard, but the explanation provided is unsatisfactory.</p>
<p>Help? Thanks-here's the link.</p>
<p>Geometry</a> question</p>
<p>Here -- to find the Triangle's area, you simply look at it from the other point of direction where AE is the base; flip it so that AE is horizontal and you will see that AE is the base and treat the other as the height..</p>
<p>Since CD = 9 is given, all you need to do is find the Base...</p>
<p>Now, we know that the triangles AEB and CDE are similar by AAA: Both Right Angle, congruent angle because of parallel lines and, (2 angles are same, the last angle is the same as well). Therefore we can conclude that the ratio is proportionate of 3... </p>
<p>Then follow like said:</p>
<p>The given information shows that the ratio is 3:9, or 1:3. Now dividing AD (4) in this ratio gives us AE as 1.
The area of AEC = ½ base x height
=1/2 x 9 = 4.5</p>
<p>Does this mean you will not get a 2400?</p>
<p>That's absolutely absurd.</p>
<p>Thanks for the answer, though.</p>
<p>wait...i'm not getting that answer
maybe i've suddenly forgotten basic math</p>
<p>but how does this give us AE = 1?
3:9 gave us the ratio of 1:3 for the similar triangles.</p>
<p>Since ACD is the larger triangle, it is the 3 of the 1:3.
So shouldn't the smaller triangle's corresponding leg, AE, by 1? As in 1/3 the size? As in...4/3, NOT 1?</p>
<p>Am I missing something here?</p>
<p>hmm...i actually felt that the question was easy. I guess having an extremely tough geometry teacher helped.</p>
<p>@bsDBer2010</p>
<p>AD = 4, as in 4 parts.
AE:ED = 1:3, which total equals 4. so AE=1</p>
<p>gahhhhhhhh i set the whole triangle as similar for some reason
yeah my bad</p>
<p>lol i was like...damn that was easy...and none of the answer choices worked...
and i was like ***...
now i know haha</p>