<p>Hey all.</p>
<p>Can't figure this math question out for the life of me. It should be easy...</p>
<p>Can anyone take a crack at it?</p>
<p>Q: What is the smallest number (larger than zero) that is divisible by the first three prime numbers, as well as the first three composite numbers?</p>
<p>Greatly appreciated.</p>
<p>what is a composite number</p>
<p>id say 120</p>
<p>Composite numbers are positive integers that are not prime. 4, 6, 8, 9, 10, 12, 14, 15, 16...</p>
<p>dan is right: So the first three primes are 2, 3 and 5. The first three composites are 4, 6 and 8. Since 6 is already a multiple of 2 and 3, ignore 6. 8 is a multiple of 2 and 4, so ignore 8. You're left with 2<em>3</em>5*4 = 120.</p>
<p>if composite = non prime, why wouldn't 1 be composite</p>
<p>I should have said composites are non-primes bigger than 1...left that part out. Sorry.</p>
<p>The number 1 is the "unit," and very special. By definition, it is neither prime nor composite.</p>
<p>First 3 primes</p>
<p>2, 3, 5</p>
<p>First 3 composites</p>
<p>4, 6, 8</p>
<p>LCM = 120, so I'd say 120.</p>
<p>thanks captin obvious</p>
<p>i love stating the obvious...btw, where did you get this question from?</p>