taylor series questioN

<p>using partial fractions find the frst five terms in the taylot series about x=0 for f(x) = 1 / [(1-2x)(1-x)]</p>

<p>f(x) = 1/(x-1) + 2/(1-2x)
1/(x-1) ~= -1 - x - x^2 - x^3 - x^4
2/(1-2x) ~= 2 + 4x + 8x^2 + 16x^3 + 32x^4
f(x) ~= 1 + 3x + 7x^2 + 15x^3 + 31x^4</p>

<p>doing math on computer makes it seem all so hard... lol</p>

<p>please explain how you broke up the function INTO
f(x) = 1/(x-1) + 2/(1-2x)</p>

<p>thank you</p>

<p>nevermind i got it</p>