Test 3, Section 4, problem 8

<p>PR 11</p>

<p>Test 3, Section 4, problem 8</p>

<p>I don't get the explanation, mostly because I don't get these type of problems.</p>

<p>Can someone explain please?</p>

<p>:-) Thanks in advance</p>

<p>Listing the question itself would help a little..................</p>

<p>There are four boys and three girls, so if no boys can sit next to each other, that means there must be three girls between each boy. --> B G B G B G B. There are three positions for the girls, that means there are 6 possible arrangements. (3 <em>2</em>1) There are four positions for the boys, that means there are 24 possible arrangments. (4<em>3</em>2<em>1). Because the arrangement of boys and girls are related you have to multiply (as oppose to adding) each resulting probablity. 6</em>24 =144...I don't know if that made sense...i'm tried my best to explain.</p>

<p>Ok...I totally get YOUR explanation, not PR 11.</p>

<p>Thanks.</p>

<p>=]</p>