<p>trig function derivative
d(sin^-1*5x)/dx</p>
<p>thanks</p>
<p>trig function derivative
d(sin^-1*5x)/dx</p>
<p>thanks</p>
<p>d[arcsin(5x)]/dx?</p>
<p>I think that’s the answer,can we simplify?</p>
<p>i think using the arcsin derivative formula, you get</p>
<p>5/[(1-25x^2)^0.5]</p>
<p>correct me if im wrong…</p>
<p>WhatsUp12321 is correct.</p>
<p>michiganfall, memorize the formulas for the derivatives of inverse trig functions!!! (for your test obvy)</p>
<p>I just found the formulas,thank you all!</p>