<p>I know this is EXTREMELY early, but we've already learned a good chunk of material in class. So, let the studying begin!</p>
<p>If you would like to participate, just post a problem for someone else to do, and complete the one above you.</p>
<p>Question: A spherical balloon is expanding at a rate of 60(pi) in^3/sec. How fast is the surface area of the balloon expanding when the radius of the balloon is 4 in?</p>
<p>Can someone tell me if this is the study guide I need to self-study? Does this book only have test practices? Because I want tutorials too.
[Master</a> the AP Calculus AB & BC, 2nd Edition (Peterson’s Ap Calculus)](<a href=“http://astore.amazon.com/petersonsbooks-20/images/0768924707]Master”>http://astore.amazon.com/petersonsbooks-20/images/0768924707)</p>
<p>what is the diff between arco and this book?</p>
<p>@lemone
Same thing, just newer. :)</p>
<p>
</p>
<p>I love related rates! Alright, so our initial values are:</p>
<p>dV/dt = 60pi in^3/s
r = 4 in
dA/dt = ?
V = (4/3)pi<em>r^3
A = 4pi</em>r^2</p>
<p>dV/dt = 4pi<em>r^2</em>(dr/dt)
60pi = 4pi(16)(dr/dt)
dr/dt = 15/16 in/s
dA/dt = 8pi<em>r</em>(dr/dt)
dA/dt = 8pi(4)(15/16)
dA/dt = 30pi in^2/s = 94.248 in^2/s</p>
<p>yeah…,its good idea
here is my question </p>
<p>q) on the curve x^3 = 12 y , find the interval at which the abscissa changes faster than the ordinate.</p>
<p>Well, I think it is (-2,2)… because…
first y’ = (1/4)x^2
Now if you think about it, the abscissa is going to be increasing faster until the slope gets to one (in this case at least). Once the slope gets to 1 it makes a shift to where the ordinate is increasing faster. So… You find when the derivative is one and that will give you your x! There ya go… either you followed that or not.</p>
<p>How about this one.</p>
<p>Find the Surface Area of y = (x^3/3) + 1/(4x), 1 is less than or equal to x is less than or equal to 3… ( 1 <= x <= 3 ) about the line y = -1</p>
<p>Good Luck! hahaha</p>
<p>Hmm, master the AP Calc book seems to be sold out everywhere. Anyone have any other book suggestions?</p>
<p>nice effort Salve! but we should note at x = 0 , dy/dx = 0 , i.e rate of change of ordinate with abscissa is 0 . so , we need to exclude it from the final answer
Final answer : (-2,2) - {0}</p>
<p>Hey Salve!, my answer is 1823/36 or 50.6388, please let me know whether it is correct or not .</p>
<p>about two months passed since the last post, how is everyone doing on preparing for the ap calc bc exam?</p>
<p>for me, I’m done learning the last three chapters (BC material) of Larson, but I’m going to have to review all of AB and BC contents again and thoroughly if I want a 5 on the exam. I will use my PR study guide march or april. Somehow, I have a feeling that there’s going to be polar graph for the FRQ this year.</p>
<p>my school has AB as a prereq for BC so we started the year with parametrics. we’re moving pretty slowly tho. when classes resume we’ll have just started series…</p>
<p>Thanks jerrry4445 for bumping this thread!</p>
<p>My school taught me everything in BC during 2009 except for Infinite Sequences and Series, I think.</p>
<p>I won’t be taking the exam until 2011 though.</p>
<p>I <3 integrals</p>
<p>How adequate do you guys think Princeton Review’s prep book is for format of the test and types of problems asked?</p>
<p>Lets bring this thread back to life since ap exams are approaching:
Which of the following series converge? I. Sum(1/n^2) II. Sum(1/n) III. Sum[((-1)^n)/sprt(n) Note: limits of summation are n=1 to n=infinity </p>
<p>A) I only
B)III only
C) I and II only
D)I and III only
E) I, II, III</p>
<p>D. I and III</p>
<p>Series I converges by p-series
Series II diverges by p-series
Series III converges by alternating series</p>
<p>What is the degree of the Taylor polynomial needed to approximate f(x) = e^x with an error less than 0.001 and x = 0.5?</p>
<p>Talor poly degree=4th: 1+ x+ x^2/2 + x^3/ 6 + x^4/ 24 ~ e^x
substitute x= 0.5 and e^x ~ 1.648375
and e^0.5= 1.648721271</p>
<p>the difference in the approximation is 0.00028< 0.001</p>
<p>A particle moves along the x-axis so that at any time t >or= to 1 its acceleration is given by a(t)= 1/t. At t=1, the velocity of the particle is v(1)=-2 and its position is x(1)=4.
a) Find the velocity v(t) for t>or= 1.
b) Find the position x(t) for t>or= 1.
c)What is the position of the particle when it is farthest to the left?</p>
<p>I’ll give you guys a hint: you need to use integration for parts (a) and (b).</p>