<p>"Find x > 3 such that </p>
<p>ln(x) < x^(0.1)"</p>
<p>How do you solve this type of problem? I plugged it into my TI-89 solver and didn't get anything. As a hint, the number is unbelievably huge.</p>
<p>is there any other criteria, like x has to be an integer? because if it is just x> 3, then stuff like x = 3.04 could technically work in that equation...</p>
<p>but yeah there must be a huge number greater than 3.05 that satisfies that equation, 'cept i have noo clue how to find it xD..</p>
<p>maybe there's a geometric sequence with the amount each value's increase is decreasing x__o if that makes anY sense..!</p>
<p>Hmm.. you might be barking up the right tree with the series idea. The problem doesn't say n must be an integer, but I guess what they mean is n > 3.xxxx... because you're right 3.05 would work.</p>
<p>I got X = 3.0597 also. I graphed ln(x) and x^.1 and then looked for the interesection which was (3.0597, 1.1183). Therefore, isn't 3.05 the answer? If you plug it back in, it works.</p>
<p>you should do what most people do... SKIP or GUESS</p>
<p>Yes, 3.06 works in the equation, but it's not the answer they're looking for which is an integer and EXTREMELY HUGE. It's a free response question, so you can't guess. I'm wondering how on earth they expect you to figure this out...</p>
<p>Just in case anyone's panicking, this is way beyond anything on the SAT or SAT II.</p>
<p>5 X 10^15 works lol</p>
<p>ln(5 X 10^15) = 36.14821...
(5 X 10^15)^.1 = 37.1447... </p>
<p>every number higher than that works too so i guess thats prolly not right</p>
<p>Andrassy, you're incredible!</p>
<p>The actual answer is n => 3.431 x 10^15, so you're answer is correct although it is not the smallest correct answer. You got the decimal places right, though!</p>
<p>What made you think of anything x 10^15? Did you just guess and check?</p>
<p>BestMiler, that's the kind of terrible advice that comes from people who don't do well.</p>
<p>i do well but if you cant get it, then what you can do in the SATS? Skipping it is the best choice rather than get it wrong</p>
<p>i just guessed it lol =(</p>
<p>sorry i couldnt be of more help...i have no idea how to do it...it had to be a huge number so after i tried like 10000 i did like 50 x 10^10 no, 50 x 10^15 yay :p. i didnt know you needed the smallest number possible though</p>
<p>or you could just use iteration and get the value quicker</p>
<p>the answer is
x>11ln0.1/1-(0.1)^11</p>
<p>yeah umm sorry to burst you bubble but 0<x<1 is the answer…</p>
<p>That’s ridiculous. How can that be on the SAT? No SAT question - by Collegeboard regulations - needs a calculator to solve. This one obviously does.</p>
<p>Here is what i got:</p>
<p>3.028777595</p>
<p>3.028777595</p>
<p>How do you solve that problem?</p>
<p>this takes me back… A possible solution may be to take the absolute value of x>3times be the cosine of 27. this will give u a huge number.Simplify it down and then approximate the number. Then take the square root of the absolute value of x>3 times the cosine of 27. This will make the number even bigger. The last step you need to divide that by the square root of 3.75. Divide that number by 2 then times by .25. That should get youre answer</p>
<p>if f(-1)=2,f(0)=3,f(2)=4,f(-3)=5,f(4)=6,f(-5)=7,f(6)=8 and g(x)=f(3x+1) then g(2)=?</p>