<p>Can you find some evidence that the cutoff was 42 for that test? There’s a lot of discrepancy over whether it was 42 or 43.</p>
<p>Well someone on the 2010 thread said that they omitted 8 and got a 800.</p>
<p>Dang that’s a REALLY nice curve CB is giving out then. 2-point curve is pretty big.</p>
<p>nvm, the curve will be 43/50 raw score minimum for an 800.</p>
<p>btw do they round down or up. lets say i got a a 42.5. Is that a 42 or a 43?</p>
<p>That’s a 43.</p>
<p>I made a lot of silly mistakes, and I mean a lot yet I still have a good chance of getting an 800. :D. Now time for physics and ush in november. Good Luck to all. Btw when does scores come out?</p>
<p>scores come out june 21</p>
<p>There was also an f(g(x)) with like f(x) was x^3 +1 and g(x) was x^2 + 1 oraybe the other way around</p>
<p>Was #49 t>= 3x or t>=3 ? D:</p>
<p>what was the boy girl problem? was it
“there are g number of girls and b number of boys. When 10 of the girls left, there were twice the number of boys”?</p>
<p>Guys, for the parametric one that asked for the y-intercept where the answer was -1/3 was 0 an answer choice?</p>
<p>Nibblin, yeah, it was that the number of boys was twice that of girls after 10 girls left, so it would be b= 2(g-10). </p>
<p>steve, yeah there was.</p>
<p>sjsharks, scores come out June 21st at 2am PST. </p>
<p>bodsquat, I think it was the other way around b/c I don’t remember expanding a cube. So it would be (x^3+1)^2+1, which would yield x^6+2x^3+2.</p>
<ol>
<li>f(3) - f(1) = 6 </li>
<li>Segment with five distinct points: 10</li>
<li>Last problem (disk/laser): B) 987</li>
<li>Complex number: 2-3i is also a root</li>
<li>Given x=√(2+√2), find (x^2-2)^2: 2</li>
<li>Angle with slopes of line l and m (2/5 and 3/5): 9.16 degrees</li>
<li>Parametric: -1/3</li>
<li>Infinite series: 2 - (1/n)</li>
<li>f(t)=2cost and g(t)=sin(t/2), find the slope of the line connecting (0, f(0)) and (pi,g(pi)): -1/pi</li>
<li>Value of x^x as x approaches 0: 1</li>
<li>Domain, range: {1, 2, 3} </li>
<li>ln x = e^-x: 0.27</li>
<li>Average speed of car: less than 50 mph</li>
<li>Graph shift, f(x) = f(x-2) + 3: two to the right, three up</li>
<li>Graph of f(x) = 1/g(x): 3</li>
<li>(a^3)^2=123.1: 2.2</li>
<li>Extending line segment, with ratio 1:2: (8, 12)</li>
<li>Perimeter of equilateral triangle: 15</li>
<li>Unit circle/chord: 2sin(theta)</li>
<li>Perimeter of triangle on a cube with side length 7: 29.7</li>
<li>Inverse graph: D)</li>
<li>Absolute value: b</li>
<li>Volume of cone: 18.88</li>
<li>Logic (if…, then…) t >= 3</li>
<li>Period: sin(2pi)</li>
<li>Average scores/min. number of judges: 5</li>
<li>1.5 radians → degrees: 85.9</li>
<li>5^(2x+1) = 96: take log of both sides and solve => 0.918</li>
<li>Point symmetry: I and III (about origin; across y=-x)</li>
<li>n(n+1)(n+2): divisible by 2 and 3, but not 4 </li>
<li>Perpendicular product: -1</li>
<li>x+x+x = x^2 : 0,3</li>
<li>sin (thetha) = x^2, what is sin (2theta): 2x^2 root (1-x^4)</li>
<li>1. f(3) - f(1) = 6 </li>
<li>a(10)=155</li>
<li>girls and boys 2(g-10)</li>
<li>x^6 + 2x^3 + 2</li>
<li>Graph is approaching y = 1</li>
</ol>
<p>Can someone please explain how you got the answer to f(x) = 1/g(x)???</p>
<p>I can’t remember the question very well, and therefore I can’t remember what my answer was.</p>
<p>They had a graph of f(x) that had a vert asymptote at x=3. It asked at what x-value would g(x) = 0, and 1/0 indicates a vertical asymptote, so the answer would be 3. </p>
<p>Also, number 37 should be +2, not +3 right?</p>
<p>Do you think the curve will be 42 or 43?</p>
<p>You’re right @aquawater98! I just fixed it :)</p>
<p>And thanks for explaining the question. I’m so happy I got it right.</p>
<p>Oh, and can anyone describe the parametric equation? The answer was -1/3.</p>