<p>When 60 minutes elapse on a correct clock, 62 minutes register on clock F (fast), and only 56 minutes register on clock S (slow). If later in the day clock F reads 8:00 and clock S reads 7:00, what was the correct time when the two clocks were originally set?</p>
<p>Ok, its actually pretty simple:
Let w = the original time the clocks were set
Let h = the true number of hours past</p>
<p>Now, it states that clock F goes 2 minutes fast.
So, simply do: 62/60 = 1.033
And for Clock S: 56/60 = 0.933</p>
<p>Now, set up two equations:</p>
<p>w + 1.033h = 8:00
w + 0.933h = 7:00</p>
<p>Now, solve by using substitution and you get h = 10.</p>
<p>Now plug this value back into one of the equations: </p>
<p>w + 1.033(10) = 8</p>
<p>w = -2.333. Assume 12:00 is equal to 0. -2.33 translates to -2 hours and 20 minutes. So 2 hours and 20 minutes before 12 is 9:40.</p>
<p>SO, the original time is 9:40</p>