<p>I was actually doing that question earlier today…its simpler than it seems… you just need to pay attention to whats given. the answer is C - if you look at figure I its 18 inches but then if you look at figure II its 14 inches, which is 4 less inches, and 2 less cups so obviously we can then understand that in figure III C = 2, the 8 is insignificant but the 8 would be a-c in figure III or simply b. Each cup is 10 inches but only 2 inches are shown except for the first one…hope that helped</p>
<p>Do it algebraically
a+4c=18
a+2c=14
use the first equation minus the second equation
2c=4
c=2
so a=10, b=8
No information for d and e.</p>
<p>You figure what is it?</p>
<p>yes sorry, the 8 is equal to b. from figure III we can see that the second pail is b+c high. since all pails have the same height, it is also a heigh. thus a=b+c
since we know that c=2, thus b=8</p>
<p>How the hell did you guys figure out how to do the first one so quickly? I spent at least 20 minutes on it and couldn’t figure out how to do it. Then I looked at the solution and just ■■■’d.</p>
<p>I am still perplexed on the circle and square question. The diameter of all four circles is 2 and each side of the square is 4. And when you make a diagonal, it’s 4 sqrt.2. Can’t seem to find the unknown radius for the small circle.</p>
<p><a href=“http://img683.imageshack.us/img683/4759/2r3e8uw.png[/url]”>http://img683.imageshack.us/img683/4759/2r3e8uw.png</a></p>
<p>Set the question up like that, and then use the Pythagorean theorem.</p>