Trig Question

Test Preparation
1

<p>56.) For x such that 0<x<(pie/2), the expression:</p>

<p>[square-root(1-cos^2(x)]/sinx +[square-root(1-sin^2(x)]/cos(x)</p>

<p>is equivalent to,</p>

<p>F. 0
G. 1
H. 2
J. -tan(x)
K. sin2x</p>

<p>The answer is H. Can you guys please provide an explanation? Please? Thanks :) :) :)</p>

2

<p>1-cos^2x is sin^2x, an trig identity. 1-sin^2x is cos^2x, another one. Thus, the square root and the square cancel out. Leaving 1+1</p>

3

<p>Just remember sin^2(x) + cos^2(x) =1
Remind you of the equation of a circle? (x^2+y^2=r^2)</p>