<p>How difficult is the trig on the test? I'm taking it in February and currently in precalculus... We haven't covered trig yet. All I know is some fairly basic concepts from AP physics; I have no idea what law of sines/cosines or anything like that is. </p>
<p>Should I definitely make a point to learn a lot more trig?</p>
<p>It varies from test to test, sometimes it helps to know the law of sines, tangents, cosines, but they sometimes provide you with the formula. If you know the basics on how to solve triangles and the properties of trianges, you should be ok.</p>
<p>just learn the trig identities, sine/cosine laws, and the unit circle. it's nothing extensive.</p>
<p>There are only four trig questions on the test. Out of sixty questions. It wouldn't hurt to learn a little trig, but your time would probably be better spent practicing what you already know.</p>
<p>Ill help you out a bit....</p>
<p>The law of Sines states: (Sin(A)/a)=(Sin(B)/b)=(Sin(C)/c)</p>
<p>A,B,C= Angle
a,b,c= Side Lengths</p>
<p>The Law of Cosines states: c^2=(a^2)+(b^2)-(2abCos(C))</p>
<p>for any side or angle you solve for just interchange the variables.... But I can't exactly remember which conditions need which formula.</p>
<p>A,B,C= Angle
a,b,c= Side Lengths</p>
<p>Hope this helps</p>
<p>SohCahToa!
and alot of times you dont even need to calculate. I remember I full on found an exact value, but then looked at the answer choices to see (for example) sqrt3/2 as those were the values simply shown on triangle in diagram.
So if its like whats the Cos 40
Just look at triangle and think "adjacent over Hypotenuse" and (pretending your adj is sqrt3 and hyp is 2) you write it like above</p>
<p>if that makes any sense what soever</p>