<p>I'm taking the SAT II Math 2 test tomorrow, and there are three questions on the Real SAT II book Math IIC test that I need help with.
Thanks in advance!</p>
<h1>35 (i guess you need the book to help me with this problem because there is a diagram)</h1>
<h1>37</h1>
<p>If the magnitude of vectors a and b are 5 and 12, respectively, then the magnitude of vector (b - a) could NOT be
a) 5
b) 7
c)10
d) 12
e) 17
The answer is A according to the book.</p>
<h1>41</h1>
<p>If N distinct planes intersect in a line, and naother line L intersects one of these planes in a single point, what is the LEAST number of these N planes that L could intersect?
a) N
b) N-1
c) N-2
d) N/2
e) (N-1)/2
The answer is B according to the book.</p>
<p>Thanks again. I'd appreciate any answers as soon as possible.</p>
<p>The triangle is a right triangle, with the right angle in the top corner. sinx (or theta) =b/2, so b=2sinx. cosx=a/2, so a=2cosx. The area of a triangle is 1/2bh, or in this case 1/2ab. So it's 1/2 * 2sinx * 2cosx, which simplifies to 2sinxcosx, letter E. </p>
<p>I can't help you with the other two, sorry. I didn't understand those them either. </p>
<p>Did you get 44, though? I have no clue on that one....</p>
<p>Since all of the planes intersect, none of them are parallel. If you draw a line parallel to one of the planes, it won't intersect that plane, but it must intersect every other plane.</p>
<p>Magnitude doesn't include direction. To find the maximum resulting magnitude, add the two magnitudes (5+12=17), to find the minimum resulting magnitude, take the absolute value of their difference (|5-12|=|-7|=7). Five is the only number not in between 7 and 17, so it is the answer.</p>
<p>+------------>----->+ 17 units from start, maximum magnitude</p>
<p>+------------>
__(tab) <----- 7 units from start, minimum magnitude</p>
<p>buminapark, i know this is late, but hopefully you're on the west coast and haven't taken it yet..</p>
<h1>44</h1>
<p>I'm not sure if I did it the right way, but I got the right answer...
the ratio between the two radii is 4/6=2/3. If h is the height of the cone, then h-8 is the height from the cross section to the tip of the cone. Assuming that the ratio between the two heights is the same as the ratio between the two radii, we have (h-8)/h=2/3.
3(h-8)=2h
3h-24=2h
h=24.</p>
<p>Hope this helps, and good luck on the test!</p>