<p>Okay here is the problem.</p>
<p>According to the 2000 Census, 58.3 percent of women worked. A county commissioner feels that more women work in his county, so he conducts a survey of 1000 randomly selected women and finds that 622 work. Using alpha equals .05 is he correct. Assume the data is normally distributed.
*FIND ALL OF THE CRITICAL VALUES, THEIR RAW VALUES, and the 95 PERCENT CONFIDENCE INTERVAL</p>
<p>I got the answer fine, but I can't get the CI because I don't know the standard deviation and I don't know what raw or critical values are.
Thanks a ton.</p>
<p>Anyone??? This hw is due tommorow and this is my last problem.</p>
<p>standard deviation = sqrt((p[null])(1-p[null])/n)</p>
<p>PS - how did you get the raw values (using a z-test, i would presume) without knowing s, since the formula is p[sample]-p[null]/sqrt((p[null])(1-p[null])/n)?</p>
<p>this is a Proportion..
use PropTest</p>
<p>Here is what I did, I did a PropInterval to find the confidence interval and since it was a Z test, I found the corresponding critical value on the chart in my book and then using that value, I plugged it into the Z Score formula to find a theoretical x bar and then got it right.</p>