<p>wellar - they will issue camp invitations by phone. The people who do not make the team will find out when the names are listed on the aapt.org website. (I'll post something if I hear about anyone getting called)</p>
<p>texas, thanks! Is a semi-finalist a big deal to addmission for HYPSMC or only a finalist does?</p>
<p>Bump... .</p>
<p>Oh, I think semi-finalist is a big deal! That puts you in the top 10% or so of test takers, who have already been identified by their teachers as the strongest physics students at their schools. And there are only 200 people in the country who get to that level. Even the top magnet schools like Thos Jefferson only get a very small percentage of their physics students to the semi-finals. National recognition is always good.</p>
<p>Your message is so helpful and encouraging. Wish you had your own website for us newbies</p>
<p>Wellar - Thanks for the kind words. I got involved in math and science competitons because my son was interested, and ended up in charge of a whole group of interested kids. Many people, both adults and students, were helpful to me when I was figuring this stuff out, and I enjoy giving that back. Another forum where you can find people who are involved in contests of various kinds is <a href="http://www.artofproblemsolving.com%5B/url%5D">www.artofproblemsolving.com</a>.</p>
<p>Looks like the USA Physics team invitations are out!</p>
<p>Anyone else get in?</p>
<p>I received a form in the mail. The form states that participants should agree to a number of stipulations, one of which states "only one national/international compeition" and "no academic training camp before June 26." It seems to me that this refers to other olympiads, such as Math Olympiad and Computing Olympiad. However, I do know one person who was on the physics traveling team last year and also went to MOSP (Math Olympiad Summer Program), which seems to be against their stipulations. My situation is that I've gone to MOSP in past years and could qualify this year. Yet, MOSP invitations won't be made until after the USAMO, which is Apr. 19-20, so I really don't know what to do. Does anyone know about this (particularly someone who has gone to the USAPHO camp before)?</p>
<p>I guess I didn't make the cut, no mail for me. :(</p>
<p>Forgot to say congrats michigan99! :)
I would just give them an email (<a href="mailto:aapt-prog@aapt.org">aapt-prog@aapt.org</a>) and ask if it's alright. If they say you have to choose one, well then you have two great choices!</p>
<p>Hi every1,</p>
<p>does anyone know the answer to one of the last questions in 2004 multiple choice exam? It's the one about there being two equal masses of copper and gold at 100 degrees Celcius each. If copper melts 100g of ice, how much ice does gold melt?</p>
<p>I tried looking at every book but I couldnt find a formula involving Molar Mass and temperature for solids. I reasoned that since Gold has a higher specific heat capacity than Copper, Gold will welt more ice. Is this right? But there are two options which have more than 100g of ice being melted. How do I choose which one it is. Do you use the ratio of the Molar masses of copper and gold?? helpppp lol</p>
<p>The best of my knowledge, which isn't very good, they should both melt the same. When placed in the boiling water bath, both reach thermal equilibrium with the bath. When placed on the ice, they should both melt tha same amount, one will just do it faster. At least, that's what I think.</p>
<p>asim1701,</p>
<p>The key idea is that the molar specific heats of copper and gold are approximately equal. The energy transferred from copper to the ice is nCT, where C is the molar specific heat, T is the temp. change, and n is the number of moles of copper. Same for gold, except the number of moles n will be different. The molar masses of copper and gold are 64 g/mol and 197 g/mol, respectively. So, for a given mass of copper, an equal mass of gold will have 64/197 the number of moles, or approximately 1/3. So, gold will melt about 1/3 as much as copper, or E) 32 g.</p>
<p>oh yeah. sorry. my solution assumed same moles, not same grams. michigan99's answer is right.</p>
<p>If you don't like memorizing the molar masses of elements or michigan99's solution seemed too complex, you could just realize that the specific heat capacity for copper is three times that of gold, so it will melt three times as much.</p>
<p>And congrats on making the team, michigan99.</p>
<p>o ok now i get it.thanks both of u</p>