<p>I realize you’re probably very sad that you missed a question, but denying the fact won’t help. The fact of the matter is that the answer is the semicircle in the second quadrant, and that’s that. I don’t know what videos you watched, but they most likely do not match the stipulations set in the question. I can’t make you believe me, and that’s fine. Be patient and wait a couple of hours. </p>
<p>you shall see</p>
<p>That I’m right? Great, except I know that already.</p>
<p>no, that you are wrong.</p>
<p>I don’t see how that is possible if I’m staring at my score report right now. If you have trouble comprehending such information, I’d suggest that you start off with a course in basic reading comprehension, as being able to read and understand problems will most likely greatly boost your score in future contests.</p>
<p>@tbradsworth I can and have scored consistently higher than 20 points on each test, and I personally agree with greenbat23. Would you be willing to elaborate on your curved response? What exactly are the “stipulations” set in the question? You claim “that’s that” without ANY form of evidence, support, or proof, which strikes me, from an outsider perspective as, well, ■■■■■■■■ or trolling.</p>
<p>I mean no personal offense in “■■■■■■■■,” but that’s really how you’re coming across, shutting down an answer multiple people have concluded and have supporting evidence on with a lack of any sort of demonstration of knowledge or proof.</p>
<p>@majorineverythin Again, you don’t need to believe me. I’m not going to go into much detail now as I’m unclear whether or not we’re able to be discussing questions. However, in a couple of hours, when results are released, I’m sure there will be plenty of proof for you. If credibility is what you’re worried about, feel free to check my two-year post history on these forums.</p>
<p>Frankly, your claim of lack of evidence, support, or proof strikes me as hypocritical when juxtaposed with your claim that you consistently score higher than 20 points on each test without any evidence.</p>
<p>@tbradsworth, i will continue studying my quantum physics while you continue to struggle determining the spring constant on the ap physics b exam you took two years ago. you will fall silent in a few hours.</p>
<p>@greenbat23 Quantum physics? ■■■■, we have a badass over here. I didn’t know that you could study quantum physics without basic comprehension of English.</p>
<p>Are the results confirmed to be released tomorrow? And tbradsworth, I put down the same answer you did, but I don’t think it’s correct…It would be nice if it was, though! Could you maybe elaborate on your thought process as to why the rope would behave in such a manner? </p>
<p>I don’t recall exactly what the question asked, but I think it was just about a helicopter lifting an object. I don’t remember wind conditions or air resistance being factored in. I’m not sure if this is related, but if you put a balloon in a car and drive forward, the balloon will also move in the same direction, and the slope of the string will be slanted. Anyway, I think this is some sort of pendulum-themed problem. </p>
<p>Looking forward to seeing the results, whatever they might be! Waiting is more fun than cramming for Scioly regionals, haha.</p>
<p>@Coriander23 Don’t worry, you got it right! The problem was about a helicopter with a flexible uniform cable flying at constant speed with air resistance factored in. There was no object at the end.</p>
<p>Again, I’m not entirely sure we’re able to discuss questions now, so I’ll wait until after scores are released.</p>
<p>@Coriander23, unfortunately you got it wrong, but it’s just one question and you’ll still likely pass! The problem was indeed about a helicopter with a flexible uniform cable flying at constant speed with air resistance factored in. There was no object at the end. @tbradsworth, please stop raising people’s hopes only to have them be crushed later.</p>
<p>@Coriander23 Don’t mind greenbat23. He’s still struggling with pre-school-level reading and as such should be ignored.</p>
<p>Mind explaining the answer for us non-believers?</p>
<p>If you want evidence, here’s my explanation:
Every differential segment of the string will have the same net tension force acting on it, since there are effectively two tension forces on it - one from above pulling it up, and one from below pulling it down. The vertical component of the tension balances gravity, resulting in a forward-directed net force, which depends on the angle. A simple free-body diagram and calculations will give you T = mg/tanθ, where θ is the angle from the vertical.</p>
<p>Air resistance is constant and proportional to the cross-sectional area (and thus angle) and the speed (which is constant, as stipulated in the problem). This gives you something like F = CLcosθ*v^2, where C is a constant and L is the length of the segment of string.</p>
<p>Both of these are functions of θ. For the string to be in equilibrium - still moving relative to the ground, but with zero net force, the two forces must be equal. This can only occur at one value of θ, meaning a curve cannot be a configuration in equilibrium - therefore it must be incorrect.</p>
<p>If you’d like to actually contribute, please point out the flaws in my argument, or (even better!) maybe come up with your own argument.</p>
<p>And by the way, 20 points really not that big of an achievement - really, it’s more of a stepping stone into more advanced physics comprehension. Most people who pass the F=ma typically show simply above-average comprehension of the physics at hand, but lack the experience and full comprehension and mastery of the material.</p>
<p>@Coriander23 I’d suggest not listening to tbradsworth for now, since he has yet to actually argue his point. He insists his answer is write in the face of support and logic, while he produces none of his own.
greenbat23 is correct though, one point probably won’t make the difference unless you’re already on the borderline - if you felt comfortable you’re probably still fine. Feel free to review my response.</p>
<p>I appreciate your providing the explanation for your solution, but there is a fundamental flaw in it. After scores are released, I will gladly point it out to you.</p>
<p>Frankly, I don’t even know why I’m continuing to reply to this thread when I know I’m right. It is not in my interests whatsoever to make you guys believe me. The answer is the semicircle in the second quadrant, but since I can’t produce any evidence without giving away any potential identifying information, <strong>take it with a grain of salt.</strong> You will all find out in a couple of hours. Good night.</p>
<p>Thank you @majorineverythin. Perhaps you should truly major in everything. </p>
<p>I propose another solution. When the helicopter is in its steady state, each rope element is moving at the same speed. This means that the force of air resistance on each mass element will be identical, and therefore we can consider the air resistance to act as a gravitational field. This situation is now equivalent to a rope under the Earth’s gravitational field in conjunction with a virtual gravitational field acting in the opposite direction of motion. The net field is a straight slanted line. The rope will take on the shape of this constant gravitational field. Thank you for your attention.</p>
<p>Was the rope massless?</p>
<p>@Coriander, we welcome you with open arms to view our solutions. Please tune out brad. We apologize for him. Let me know if you have questions!</p>