<p>The question is from McGraw's 12 Practice Tests for SAT. </p>
<p>20.) Each of the k girls in a club agreed to raise an equal amount of money to give to a charity to which the club had pledged a total of x dollars. If p more girls later join the club and also agree to raise an equal share of the pledged amount, how much less would each of the
original club members have to raise, in dollars, than she had originally agreed to raise?</p>
<p>a) x/k
b) x/(k+p)
c) px/(k+p)
d) x(k+p)/k
e) px/k(k+p)</p>
<p>Originally, I had chosen k to equal 5 and x to equal 20. Therefore, each student was paying $4. After, I had p = 5 so that there would be a total of 10 students, and therefore, each student would then pay $2. This meant that every student paid $2 left. When plugging in my numbers into the equations, B worked as 20/(5+5)=2. Unfortunately, the correct answer was E. When plugging in my variables, I could see that both E and B work. So for the future, should I always just try to pick different values for each variable?</p>