<p>lets see how many of these i got right.
1.63
2.44
3.5/3
4.16
5.2186
6.891
7.8
8.5
9.252
10.91</p>
<p>that's recursive, not explicit (as it refers to the previous term). find the 1,000 term of that sequence... you'd need an explicit formula (as posted before).</p>
<p>This doesn't have anything to do with Calculus!</p>
<p>so basically this person had a homework assignment, and you guys just did it for him/her. awesome.</p>
<p>answer explanation
1)63 [8=3+(5+0),15=8+(5+2),24=15+(5+4) and so on]
2)42 [odd positions are multiple of six in alternative manner (6<em>1=6,6</em>3=18,6<em>5=30,6</em>7=42)]
3)7/6 [add 1/6 in all terms]
4)16 [-2^2,-1^2,0^2 and so on]
5)2186 [{(3^n)-1} ‘n’ varies from 1 to 7]
6)
7)8 [odd positons are in A.P(d=2)]
8)5 [add 5,subtract 3]
9)253 [{(2^n)+previous term}] where 0<=n<=7]
10)91 [ common diff are in A.p.
where a=11,d=1]</p>
<p>correct me if i am wrong thnxx…!!</p>