<p>Sorry my diagram/handwriting isn't great, but I was kinda rushed about it. If there is something that you don't get because of me, just ask and I'll clarify.</p>
<p>Can someone answer and explain it for me? </p>
<p>THANKS!</p>
<p>Try connecting the centers of the circles with lines, you should get an equilateral triangle. So, the answer is just 8 plus the height of the triangle (hint: use the 30-60-90 triangle figure that is given to you in the formulas section of the SAT).</p>
<p>Is the answer B? Im sorry your diagrams a bit messy, if its B then ill explain to you what i did</p>
<p>Answer B.
Keyword-Tangent. Imagine a triangle. Imagine the triangle going into the 2 centers of the upper and lower (either the left or right) circle, which is the hypotenuse (8). Now drop down the perpendicular line from the centre of the top circle to point "A"(on your diagram), and then connect "A" to the side (4). This is a 30-60-90 triangle which means the height of the triangle is 4* sqrt. of 3. (which is a part of the height). Now add the 2 parts of the height that the triangle's side didn't include (which is also the circle's radius). Now since there's two parts that the triangle's side didn't include, you have to add 2<em>4(the radius) to the answer. SO the answer is 4</em>sqrt of 3 +8. Hope I explained it accurately so you can understand.</p>
<p>Yeah, it is B. I get it now. Urgh, it was so easy actually. Stupid geomerty. </p>
<p>I drew it exactly like you said fignewton and then stared at it. And sorry the diagram is messy, I didn't want to copy it with my writing on it. </p>
<p>THANKS!!!!!! I got it now.</p>
<p>Props for writing it out and then scanning it</p>