Weird Level 5 Math Question I Can't Get

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<p>Hey Guys,</p>

<p>I'm not sure why but I just can't get the answer to this question. It was on the Jan 2008 SAT, and it's a level 5 question. The prompt reads:</p>

<p>If n can be any integer such that 6 < sqrt(n) < 10, what is the difference between the largest possible value of n and the smallest possible value of n ? </p>

<p>(A) 2
(B) 4
(C) 16
(D) 62
(E) 64</p>

<p>I did the sqrt(81) = 9 which is one less than 10, and the sqrt(49) = 7 which is one more than 6, then I did 81 - 49 = 32. But 32 isn't even an answer choice!?!?! Am I going crazy or am I missing something? </p>

<p>Thanks in advance,</p>

<p>iBP</p>

<p>P.S. I'm going to write the answer in a slightly encrypted form so that you can stop reading if you want to try and solve it yourself. The Answer = the fourth letter in the word GUIDE.</p>

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<p><a href=“A”>quote=iBP</a> 2
(B) 4
(C) 16
(D) 62
(E) 64</p>

<p>I did the sqrt(81) = 9 which is one less than 10, and the sqrt(49) = 7 which is one more than 6, then I did 81 - 49 = 32. But 32 isn’t even an answer choice!?!?! Am I going crazy or am I missing something?

[/quote]
</p>

<p>n = 99
n = 37
Answer: D.</p>

<p>You fell into the trap the question set up. N can be any integer. sqrt(n) does not have to be an integer. </p>

<p>sqrt 100 = 10.
sqrt 99 <10. </p>

<p>sqrt 36 = 6
sqrt 37 >6</p>

3

<p>Wow, I can’t even believe I got tricked by this stupid question. Thank you so much.</p>