<p>I can't understand this question maybe one of you guys (and girls) can?</p>
<p>(x^2-t^2)^.5=2t-x</p>
<p>If x and t are positive numbers that satisfy the equation above, what is the value of x/y?
the answer is 5/4.</p>
<p>(x^2-t^2)^.5=2t-x</p>
<p>square both sides</p>
<p>x^2-t^2=(2t-x)^2
x^2-t^2=4t^2-4tx+x^2</p>
<p>x^2’s cancel</p>
<p>-t^2=4t^2-4tx
5t^2=4tx
divide by t
5t=4x
5/4=x/t</p>