Weird Power Series Question o.O - Calc BC

<p>For logistic growth,</p>

<p>dP/dt = kP(M-P)</p>

<p>k is your constant, P is the amount at a given time, and M is the maximum possible population/value. In that question, M is 200, so you want to factor out a k value such that you get the differential in the kP(M-P) format where M is 200. In this case, that would be choice A.</p>

<p>.2P-.001P^2 = .001P(200-P)</p>

<p>Ah thanks Pioneer. My teacher always taught our class that the equation to use is dP/dt = KP(1 - P/M)</p>

<p>Is this the same thing?</p>

<p>Is it a problem if I don’t remember seeing this question?
There are two forms, right?</p>

<p>i’m so sure i saw that first problem on the ap calc bc mc today. and i got it wrong. if only i had come on this forum yesterday night t_t</p>