<p>Cal I, II, or III, or Diff EQ?</p>
<p>I'm in my first Cal course ever. I made a 90 on the first exam, and I'd be surprised if I did as "well" on the second one I took today. Heh. Working on the homework sets the nights right before the exam is not a good idea! I've been having to learn things right before, rather than review, which is the way it should be. I need to practice better study habits.</p>
<p>Calc II is generally seen as the biggest weeder.</p>
<p>I think Calc III is the hardest class I have taken out of everything.</p>
<p>EVERYTHING everything?</p>
<p>I wondered the same thing. It is possible, but I think the difficulty is more a function of the professor than the material...</p>
<p>MultiV II?
Maybe DiffEqs II?</p>
<p>I'm sure it didn't help that my prof wasn't the best at speaking english. We had a lot of proofs too, which I'm pretty bad at.</p>
<p>I hate formal proofs. Leave those to the mathematicians! Haha.</p>
<p>Calc III is harder to understand, but easier to do.</p>
<p>I think Calc II was the hardest with taylor and maclaurin series..Calc III is pretty easy..</p>
<p>Im at cal too, most people I know did really well on the first math 1a midterm. My roommate got %100. Personally I think calc 3 (math 53) is the hardest computationally and seeing things in 3d. I'm in math 54, or linear algebra and differential equations,and so far the computation in it is not hard, but the math is very abstract. All about subspaces, transformations, sometimes defining new ways of adding and multiplying. Calc1-3 is a lot of learning processes like integrating, solving series, but math 54, has lots and lots of math vocabullary and doing things that you cant really visualize.</p>
<p>3D isn't hard. 5D is :)</p>
<p>field flow (time dependent):
(x,y,z,f(x,y,z,t),t)</p>
<p>but is Calc II at Cal like Vector Calculus?</p>
<p>No that would be calc 3. Calc 2 expands on calc 1 and introduces new integration techniques, and introduces sequences and series, which I hate.</p>
<p>how is calculus different from algebra?</p>
<p>Honestly, once you get past the math it really doesn't seem as hard. System modeling seems to have no bounds to difficulty.</p>
<p>
[quote]
3D isn't hard. 5D is </p>
<p>field flow (time dependent):
(x,y,z,f(x,y,z,t),t)
[/quote]
</p>
<p>That would be 4D since f is a function of the other variables.</p>
<p>no it's 5d, the function itself becomes another dimension when graphed in space. f(x) has only one independent variable x, but it is 2d because of f.</p>
<p>here's my ranking of calc classes...from easy to difficult</p>
<p>calc III, calc I, calc II</p>
<p>f(x) vs. x will give you a 2d graph, but it is only a one dimensional problem. Usually when people talk about 3D calculus problems, they are talking about somehting in x,y,z space, right? </p>
<p>The equation would be, for example, f(x,y,z,t) = (10x +10y + 3z)*t</p>
<p>If I want to graph f(x,y,z,t), p(x,y,z,t), b(x,y,z,t), g(x,y,z,t), k(x,y,z,t), x, y, z, and t it is still a 4D problem, not a 9D one just ebcause you want to graph things.</p>
<p>yes, 3d is about xyz space, consider a sphere with equation x^2 + y^2 + z^2 = 1 </p>
<p>we often assign one spatial direction to represent the value of the function - in the 3D case z is often used to represent the range; if z = f(x,y) then the same equation of the sphere would become f(x,y) = (1 - x^2 - y^2) ^1/2</p>
<p>that would not change the function from being 3D to 2D. a sphere is 3-dimensional.</p>
<p>and no f, p, b, g, k would all be separate 5D functions, not 9D.</p>