<p>People always joke about how IOE is a joke compared to other engineering major. I hear Ross is pretty easy too (compared to engineering) but the students there get a lot more respect than IOE kids. So which one is truly easier: Ross or IOE.</p>
<p>what’s the point of this post? few people actually have experience with both programs, so most the answers you’ll get are biased one way or another.</p>
<p>A lot of people double major in both IOE and Ross. Also, a lot of IOE kids take a couple of Ross classes</p>
<p>i would not say a lot do. i used to be doing the dual degree (spent my soph year in both programs) but dropped Ross halfway through junior year to add another major. i know all the dual degree bba + ioe rising/graduating seniors and there are at most a handful each year. i’m pretty sure only one of them has a CC account, and he rarely ever logs on anymore. to answer your question, though, it depends on which courses you’re comparing, but in general the content in Ross courses is much easier than the content in ioe courses.</p>
<p>Full disclosure: I’m in Ross, I have a lot of friends in IOE.</p>
<p>I’d say the competition at Ross is higher while the material at IOE is probably “harder” in it being more quantitatively challenging but obviously everyone’s strengths are in different areas. Either way you’ll be around a lot of smart kids.</p>
<p>i agree with maizeandblue for the most part. the culture at the 2 colleges is much different, which leads to the difference in competition. recruiting at ross is much more structured and transparent with students gunning for x amount of spots on interview lists. basically everyone knows who is recruiting for which firms. you don’t really have students competing against each other like that in ioe.</p>
<p>Oh, and coming from a non-IOE kid, if you’re one of those engineers who calls IOE IOEasy or Instead Of Engineering, then, ya know, see ya never in the Dude. You’re just wasting your time toiling away for a MechE degree and you’ll end up making no more than IOE kids.</p>