<p>In the xy-plane, a circle with radius 5 has its center at (0, 0) and a second circle, with radius 2, has its center at (8, 0). If P can be any point on the first circle and Q can be any point on the second circle, what is the minimum possible distance from P to Q?
(A) 1
(B) 2
(C) 3
(D) 5
(E) 8</p>
<p>Can someone explain to me why I picked B..?</p>
<p>I think the answer is A. Just draw the two circles. The radius of the first circle is 5 so pick the point at (5,0). The second circle has a center at (8,0) and a radius of 2. So pick the closest point which is (6,0). Therefore 6-5=1. And you picked B because you thought it was right?</p>
<p>Just find the distance between the two centers and subtract the two radii. Obviously the centers are 8 units apart. The firstr circle goes to (5,0) and the second reaches back to (6,0). These are the optimal points to place P and Q. Thus, the distance between them is 1 (Option A).</p>
<p>Sorry if my post was misleading. My post is simply an expression of lividity and contempt without expletives. Sarcasm doesn’t flow too well over the internet…</p>
<p>Yeah I just got the November SAT scores back last week and got a 780. I got one medium question wrong. If I were to get anything wrong because I actually didn’t know how to do it, it would most definitely be a hard one. I probably circled the wrong one or misread the question. Also, how do you know which question you got wrong? It only tells me what type of question I got wrong not which one I actually missed.</p>
<p>I just got the QAS back from the October test. It contains a sheet with the answers you chose as well as a copy of the test booklet. That’s how I knew.</p>