Thank u so much WasatchWriter… This makes complete sense to me…
Wasatchwriter pls can I post some essays…? Do u mind checking them?
There is only a week left for my exam
So if u could help me…
@abcdefgh3 You should post that question to the whole board. I read essays for a living, so doing it here is not very fun for me.
I already posted the essays to the whole board…
But no one checked…
Guys a maths question from princeton
The charge for the first quarter mile of a taxi ride is $1.40,and the charge for each additional quarter mile is $0.20. If the total charge for a certain taxi ride is $5.00,what is the length of this ride, in miles?
A) 9/2
B)19/4
C)11/2
D)19
E)25
Really baffled… Please help… This quarter thingi is confusing me
Thanks in advance
5.00 - 1.40 = 3.60 (+ 1/4 mile)
3.60/.20 = 18/4 miles (+ 1/4 mile)
19/4
(B)
Pls explain marvin100…
Total is $5.00. Subtract $1.40 for the first quarter mile (but remember that it represents 1/4 mile traveled!). Now you have $3.60, which you know is composed of 1/4 mile intervals billed at .20 per 1/4 mile. 3.60/.20 is 18, so you have 18 quarter miles plus that first quarter mile that was billed at $1.40, so a total of 19 quarter miles. Expressed in units of “miles” as the question requires, your total is 19/4 miles.
Thank u so much for an awesome explanation marvin100…
Guys a difficult math question from barrons
Central state college has three sections of math 102. If four students jill,phill,mill and will decide to transfer from math 101 into math 102,in how many ways can the students be assigned to the three sections if each section must receive at least one new student?
A)12
B)18
C)24
D)27
E)36
Guys pls help me…
Thanx in advance
One more question guys
one-fifth of the cars in a parking lot are blue and 1/2 of the blue cars are convertibles. if 1/4 of the convertibles in the parking lot are blue, then what percent of the cars in the lot are neither blue nor convertibles?
I like to make a table for these:
Color/Roof Blue Not Blue Total
convertible T/10 3T/10 4T/10
not convrt. T/10 5T/10 6T/10
Col. subtots T/5 4T/5 T
Answer: 5T/10=50%
“Central state college has three sections of math 102. If four students jill,phill,mill and will decide to transfer from math 101 into math 102,in how many ways can the students be assigned to the three sections if each section must receive at least one new student?
A)12
B)18
C)24
D)27
E)36”
Solution:
This is a permutation of combinations. Since there are 4 students and 3 classes, we have to put a group of 2 students into one class and a group of 1 student into each of the two remaining classes.
Step 1: Assume we put the group of 2 students into class 1, 1 student in class 2 and 1 student in class 3.
Number of ways to do this= C(4,2)xC(2,1)xC(1,1)=6x2=12
Step 2: We can also put the group of 2 students into class 2 or class 3, so we have to multiply the result from Step 1 by 3. 3x12=36. Answer. E
Thanx Plotinus
But pls can u elaborate it a little…especially step one
One cr question from barrons
For some people language has ________ interest;different language systems,history and relationships,are considered worth investigating in themselves
A pragmatic
An anachronistic
An intrinsic
A theological
A Utilitarian
Pls explain
Thanx in advance
The clue is “worth investigating in themselves” and the answer is “intrinsic”–if the interest is “in themselves” it is not dependent on external factors, so it is “intrinsic.”
Step 1 counts the possible outcomes of a compound event made up of 3 events:
Event 1: pick the two students who will go into Class 1.
Event 2: pick the 1 student who will go into Class 2.
Event 3: Pick the 1 student who will go into into Class 3.
We determine the number of possible outcomes for each of the three events, and then multiply these numbers together to find the total number of possible outcomes for the compound event (this is the counting principle).
Event 1: We assume that two students are going into Class 1, so we have to pick 2 students starting from a group of 4. The number of groups of 2 that can be formed starting from a group of 4 is C(4,2) or (4x3/(2x1)=6.
Event 2: We assume 1 student is going into Class 2. We have to pick 1 student from the remaining students. There are 2 students remaining, so there are 2 possible outcomes.
Event 3: We assume 1 student is going into Class 3. We have to pick 1 student from the remaining students. There is 1 student left, so there is only 1 possible outcome.
6x2x1=12.
In the original solution I treated all three events as forming combinations to give a more general solution. However, it is probably clearer just to say that in Event 2 we pick 1 student from 2 and in Event 3 we pick 1 student from 1 rather than to say we form a combination of 1 starting from 2 and a combination of 1 starting from 1.
Okay now I get it… Thanks a ton Plotinus and Marvin 100…
Super easy question… Level 1…but still got confused between 2 options
I can never understand the difference between past perfect and simple past
This week’s independence day fireworks BEING much more exciting than last year’s.
Being
Had been
That was
Was
Were
Pls explain… Only 2 days left for my exam
Thanks in advance