<p>@nicobella It was something with f(x) and g(x) and you had to solve for a</p>
<p>@nico
It was like something like 2 quadratic equations with unknowns a, b, and c, and you are given two functions, and you’re supposed to solve for a.</p>
<p>ohhh ok i think i put 3 for one of them so hopefully it was that one</p>
<p>@RishabC297
what was the question for the grid-in with the answer of 7?</p>
<p>Also, for the reading one, why isnt it “summary of injustices” instead of “litany of complaints”?</p>
<p>@dn4144.
Perimeter triangle 24
sides 10, x, x.
x = 7</p>
<p>@RishabC297</p>
<p>I think injustice is too strong of a word.</p>
<p>oh ok yeah I got that one. I just forgot about it lol thanks</p>
<p>Expected Scale if any?</p>
<p>what was the question where the answer was 36, if remembered?</p>
<p>That was the one where 3 + 1/x = 9.
Therefore, x = 1/6.
The problem asked for x^-2, which would be 36.</p>
<p>for the one where it had a cube with two pyramids coming off of it…</p>
<p>i got 200… what did you guys put and why?</p>
<p>… parallelogram question… did they specify a value range for n?</p>
<p>That was the one where 3 + 1/x = 9.
Therefore, x = 1/6.
The problem asked for x^-2, which would be 36. </p>
<p>^</p>
<p>ooh ok i got that thanks!</p>
<p>@antarticice101</p>
<p>n had to be between 2 and 4, so i chose 3 as the n value and got 4 as the answer</p>
<p>why is it 100 + 50root3?</p>
<p>its 25<em>4 for the cubes surface area (not the sides w the pyramids) and then 1/2 base times height, which is 2.5</em>5, times four… which is 50… then there are two of those… so i got 100+50+50… why is that wrong?</p>
<p>K can be several values. 3<k<5, so any number that satisfies that inequality will work.</p>
<p>@dns031 </p>
<p>the height of the triangle was 2.5root3. So it would be .5x5x2.5root3 x 8 = 50root 3</p>
<p>Then plus 25 x 4 for the square faces so the answer is 100+50root3.</p>
<p>what was the question w/ the answer 25?</p>
<p>@dns031, since each edge has a length of 5, the triangles in the square pyramids are equilateral. The formula for the area for an equilateral triangle is s^2*root3/4, which is derived from 30-60-90 triangles. since there are 8 triangles, the total area for the triangles is 8 * 25root3/4, or 50root3. When added with the surface are of the four sides of the cube, the answer is 100 + 50 root 3.</p>