<p>Guys, I think we should just let the 'n’th term problem rest. There’s obviously two different groups of people who answered two different answers, and while one of them is right, nobody will know absolutely for certain until the scores come out. </p>
<p>Also, I’m so ****ed at myself over the dice one. For some reason I only thought of combinations 1 6, 6 1, and 6 6 and thought “well gee that’s 2/3” so that’s what I put. And I never thought of the 1 1 combo. :(</p>
<p>*****, i hate math so much. i was hopeless for this section after like question 30.</p>
<p>Was the midpoint one like -16?</p>
<p>@Somewhere i think i put -16</p>
<p>what was the midpoint question?</p>
<p>it was -16</p>
<p>@bornagain i mean the wording of the question</p>
<p>Couldn’t remember the exact points. For sure though, the midpoint question answer was -16. I believed the question had to do something with a given point that’s on a line segment and you were given the midpoint of that line. You had to calculate the x-coordinate of the other point of the line. Does that make sense???</p>
<p>Hi guys. So, regarding the infinite product of the fractions for the form (n/n+1), with n starting at 2…I am currently a junior, and i’ve qualified for AIME 3 times. I will potentially qualify for USAMO this year. So, I know ACT math pretty well. I just want to clear up any confusion caused by trolls. Trolls sucks.</p>
<p>Anyways, here’s a really simple way to reach the answer. Think about this, if you have (2/3)(3/4), you just get 2/4. Similarly, (2/3)(3/4)(4/5) = 2/5. The fact that every “inbetween” numerator-denominator integer pair cancels is called telescoping.</p>
<p>So, the final product in terms of n is just 2/(n+1). As n approaches infinity, this value clearly approaches 0.</p>
<p>If there is any fault in my logic, please point it out trolls.</p>
<p>^■■■■■ Thanks for that. I just don’t see how or why the trolls continue to argue that 1 is correct. Trying to trick people into thinking that it’s correct won’t change the real answer!</p>
<p>omg leave it alone! There will never be a consensus reached! I will be taking MVC next year while still in high school, and you don’t see me bragging about my math accomplishments! Your credentials mean nothing to me, or anyone else who thinks the answer is one. Even the most brilliant mathematicians can misread problems. Stop talking about this one!</p>
<p>and wcclirl, you are actually an idiot. CC should take away your posting privileges.</p>
<p>lol. Well if I’m an idiot, how did I not miss a single problem on the math section when you missed at LEAST 1?</p>
<p>Oh, and by the way, a consensus HAS been reached. You’re the only person still arguing that it’s 1. Almost everyone else who had 1 agrees that it was 0. Just because you are a poor sport about it doesn’t mean that a consensus hasn’t been reached.</p>
<p>Finally, I find it funny how you make fun of our credentials saying that they mean nothing when you then go on to brag about the courses that you <em>will</em> take. Guess what? I could take “multivariable differential calculus with sprinkles of pixidust and magic” but it doesn’t mean I will do well or know the material. In fact, I will be taking senior college level math in about 4 or 5 years too lol.</p>
<p>EDIT: Also, regarding my posting privileges… I believe that I have helped this thread out way more than anyone else has by organizing about 25% of the answers on the entire math section into a single post for people to see. What have you done? Oh that’s right, you’ve TROLLED</p>
<p>Ugotserved, there is nothing to misread. The problem provided an inifinite product, often denoted by a capital Pi, though of course that wasn’t used in the problem. And i’m providing my credentials because they are fairly legitimate, and it certainly provides comfort to the kids who got the right answer of 0 after the stress you may have put them through.</p>
<p>And MVC? I don’t usually brag, but just for you: I covered MVC in a week over summer break. I’m studying Combinatorial Graph Theory and Real Analysis. This is not the point of this thread, the point of this thread is to provide answers with legitimate support. Stick to that instead of causing kids grief.</p>
<p>@ Iris</p>
<p>Actually, in the Real ACT book, a -3 would typically be 34. I thought this test was much harder than any of the ones in the book. My guess is:</p>
<p>59/60 = 36
57/58 = 35
56 = 34
55 = 33</p>
<p>Hey, what was that problem that looked something like this:</p>
<p>X^2/(81) + y^2/(64)</p>
<p>I can’t really remember.</p>
<p>Not trying to ■■■■■ here
but if the problem was:
(n-1)/(n) times (n)/(n+1), then it would be the same as</p>
<p>as limit of n —> infinity, (n^2 - n)/(n^2 + n)
and according to the infinity limit rules, it approaches 1.</p>
<p>can someone explain why it is wrong?</p>
<p>inTheoWeTrust, the answer was I believe (9,0) for that question, where the equation was (x^2)/81 + (y^2)/64 = 1.</p>
<p>That was not the problem. The problem (the way most people interpreted it) was multiplying all of the terms in the sequence, from 2/3 all the way up to (n-1)/(n) and (n)/(n+1).</p>
<p>That is how everyone here except 2-3 people interpreted it. They read the question as you stated it. As we do not have the test, we cannot confirm what the wording of the question was. The majority opinion was that all of the terms were multiplied together, but this argument has been going on for way too many pages now and a consensus will not be reached.</p>
<p>Does anyone remember some of the easier ones? I just want to make sure I didn’t make a stupid mistake.</p>