<p>Dwayne has a newspaper route for which he collects k dollars eacy day. From this amount he pays out k/3 dollars per day for the cost of the papers and he saves the rest of the money. In terms of k, how many days will it take Dwayne to save $1,000?</p>
<p>the answer is 1500/k, which I got by plugging in. can anyone give me a tip on doing it algebraically?</p>
<p>Chochocho- sit down and do some reasoning. if he makes k a day and then pays out k/3 a day for costs, then the total money he makes in a day is k-k/3.</p>
<p>To find the amount of days (we'll say x) it will take him to make $1000, we just use common sense.</p>
<p>x(k-k/3) = 1000</p>
<p>x(2k/3) = 1000</p>
<p>x = 1000/(2k/3)</p>
<p>x = 1500/k</p>
<p>dodgerblue- good reasoning, the answer, however, isnt in $</p>
<p>ok guys, another math prob.<br>
If r^5 - (r^4)*(s) = 96 and r- s = 6, which of the following could be the value of r +S?
A) -10
B) -6
C -4
D 2
E 10</p>
<p>sonar, you forgot to consider the fact that the answer to r^4=16 can be r= -2 as well as +2. if you substitute -2 in the equation r-s=6, s= -8.
-8+(-2)= -10</p>
<p>so A should be the right answer. anyone get anything else?</p>