<p>AVT is what my teacher calls the MVT for integrals (I don't know which one is the correct terminology, but I assume AVT= Average Value Theorem).</p>
<p>Basically what it says is the average value of f(x) on [a,b]= (1/(b-a))fnInt(f'(x), x, a, b).</p>
<p>Note that that is not f(x) in the fnInt; it is f prime x.</p>
<p>Or if you want to go simpler, the average value of f(x) on [a,b] also = f(b)-f(a)/(b-a) (which is essentially what the above mentioned integral turns out to be anyway...)</p>
<p>Mean value theorem is different guys.</p>
<p>Mean Value theorem states that if F(x) is continuous on [a,b] and differentiable on (a,b), there is c makes f'(c) = f(b)-f(a) / b-a</p>
<p>What are the usages of Mean Value theorem ?</p>
<p>MVT is for when you want to find the average value...usually you'll have a table....</p>
<p>AVT is what ILIKEDICE said</p>
<p>It's tricky to know when to use the MVT and when to use the AVT.</p>
<p>MVT is the average RATE OF CHANGE over [a,b]
AVT is the average VALUE of a function over [a,b]</p>
<p>That doesn't help much, does it lol. You kinda know when to use what, just because AVT requires an integral.</p>
<p>MTV- think of slope
AVT- think of area under a curve
Both are averages </p>
<p>does that help? I'm so screwed for this test too. I should probably be studying right now but I'm hungry and I want to eat dinner first lol</p>
<p>screw it we got until wednesday....lol</p>