<p>So far I love it.. so easy..
However I can't seem to do this. (I am stuck here. Won't look at answer unless with explanation)
I am finding derivative of Ln (x) so i did this
LN (X+H) - LN(X) / h
LN (X+H/X) / h
LN (1 + h/x) / h
h comes to top
1/h Ln (1 + h/x)
1/h can act as exponent
ln (1 + h/x) ^ 1/h</p>
<p>Now where dO i go from here.. I am so stuck.</p>
<p>NM I solved it :D
I forgot (1 + h)^1/h = E
So this is what I did
Since the above statement is true, this statement must also be true
LN (1 + H/X)^X/H
So then To get that I simply times it by X / X (the whole equation)
X LN (1 + h/x) ^ 1/H all over X
So thats LN (1 + h/x) ^ x/h all over X
Thats simply 1/X
WOOT i always get this good feeling when I do a math problem by myself :D.</p>
<p>dude the limit definition of a derivative is useless if u know it already. ln(x) is predefined to be 1/x</p>
<p>I didn't know it already... i was trying to do it w/o looking at book until I got final answer.</p>